2 sin(x)-sin(2x) х-sin(x) lim X→0

Q: 7) lim (Ln(x) – x) X→∞

A:

Q: lim_(x → 0) ((x/(1-cosx) - (2/x))

A: Use L'Hospital Rule

Q: Lim x->infinity (cos 1/x2)x^2

A: To evaluate the below limit

Q: lim 1- cos () X00

A: Given, limx→∞1-cos1x To Find the value of this limit function.

Q: lim x→0  2 ln x.

A:

Q: lim (cos x)x² 1/x2

A:

Q: lim x- Vx x-0

A:

Q: 1-sinx x-1-cos2x 9) lim 10) lim TC X- sinx-cosx TL X- 4

A:

Q: sin 3x lim .2 x0 4x -x

A:

Q: Lim メーラル sin2x x² 2.

A:

Q: ((주)' lim x (1- cos () COs X->- 00

A:

Q: (+) C lim x sin sin(3x) lim- 0 sin(4x) sin (x-1) lim 1 1-x+x² -x'

A:

Q: lim x approaches 0 ................ (x^2 - 1)(2 - cos x)

A: To find the limit of the function as x approaches 0, the function is given as follows: x2-12-cos x

Q: 2Tan 'x -x 9. lim, 2x – Sin^x

A:

Q: x sin(3x) lim x→0 sin(x2)

A:

Q: lim xS0 cos2x - cos x / x^2

A: To find: limx→0 cos2x-cos xx2

Q: lim +h)-f(x) h→0 >- f(x) = v5x + 1 when x %3D h 5

A: Given:  fx=5x+1x>-15 To Find:  limh→0 fx+h-fxh=?

Q: lim   ln(cosx) x → π/2

A:

Q: lim (4 + (x + y} ) In(x² + y)) (х.у) - (0,0)

A:

Q: limx→0  xcos(x)-sin(x)/x^3

A: Given: The limit limx→0xcosx-sinxx3, To find: The value of the limit.

Q: Lim 1- Cosx て X-)0

A: Given: L=limx→01-cosxsin2x We know that 1-cos2x=2sin2x…

Q: x2-4 1) lim x-2 x-2 sin 2x 2) lim 1 1 3) lim(-- X-0 x VX

A:

Q: lim 1- cos ( X00

A:

Q: 3/x – 3 (k) limx→-∞ 5 - x x³ +1 (1) limx→-∞ Cos -0- x6 +x5 + 100

A: For (k), We need to find limx→ -∞ x-35-x3. So,            limx→ -∞ x-35-x3We know that,…

Q: lim sin (–3 x z) = z-3

A: To find- the limit.

Q: lim zx+xて Xー→3 メ-3

A: Apply L hospital rule

Q: 1-x c) lim- x1 1-Vx こ 11- sin x d) lim エー→0

A:

Q: lim COos x –1 x→0 x² – x³

A: To evaluate the given limit.limx→0 cos x-1x2-x3

Q: lim (-4 0 sin x x

A: Let ,I=limx→ 01sinx-1xTaking cross multilplicationI=limx→ 0x-sinxxsinxI=0-sin(0)0sin(0)I=00Which is…

Q: Find the limit

A:

Q: 3) lim Lnx .tanx x-0+

A: Use lim sinx/x and L'Hospital law .

Q: 1-sinx x²-49 b. lim x→7 x-7 lim C. lim X→00 x²+1 a. X 1-cosx

A:

Q: 2 sin a-sin 2x limr x-sin x

A: use l hospital rule

Q: x2-4 1) lim x-2 x-2 sin 2x 2) lim 1 3) lim(-- x0 x V

A:

Q: 26.lim(1 + cosx)2secx x 2 27.lim (G– x) tgx 27.lim ( - 2

A:

Q: 2 sin(z) – sin(2z) lim -10 z- sin(z)

A: We use L'Hospital rule to solve this limit problem.

Q: Lim e^x +e^-x-x²-2/sin²x-x² when x approaches 0

A: The given limit is, This limit is in 0/0 form, so we can apply L’Hospital's rule,

Q: Lim Cos t X-2SM X2

A: limx→2cosπxx-2sinπx

Q: lim -Vx + e* + sin(x)cos(x) 1+ In (x)

A: limx→3-x5+ex1+ln(x)+sin(x)cos(x)=-35+e31+ln(3)+sin(3)cos(3)

Q: 1 lim x-0 (sinx ズ→ X.

A: Evaluate the limit limx→01sin x-1x. Rewrite the expression: limx→01sin x-1x=limx→0x-sin xx sin x…

Q: +lim x-0 e -x - 8x ex - e x - sin x

A:

Q: 2 sin x-sin 2x lim х-sin x 3 O -3 6 -6 о O O

A: Given- limx→02sinx-sin2xx-sinx To Find- The valuie of the limit.

Q: 5 sin(6x) lim x→0 3x

A:

Q: lim x (1 – cos X→-0

A: limx→-∞x1-cos1x

Q: 1 - cosh x lim x→0+ ln(x² + 1)

A:

Q: Find the limits

A: Given,                     lim(x,y)→(0,ln2)ex-y     And we have to find its limit.

Q: lim Vx+ 2/x - Jx)

A: NOTE: Refresh your page if you can't see any equations. . multiply and divide by

Q: lim x-0 sin 3x

A:

Q: lim Sin2x X+0 +1 - 1

A:

Q: lim cos xx x-0

A:

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.