2) Two parallel-plate capacitors are constructed using dielectric materials with dielectric constantsK13 and K, = 5, as shown in Figure. Parallel-plates have the area A = 0.7 m². The distance isd = 0.05 m. A potential difference of AV = 24 V is applied to the circuit.(a) Find the equivalent capacitance of the system.(b) Find the potential AV1. (8=8.85×10-12 C²/N×m²)K1A/2AV1K2A/2K2 K1A/22d/3 d/3K2A/2AV = 24 V

Answered: Image /qna-images/answer/e97f35b7-a10e-4b0e-8d04-a3c64893d457.jpg

2) Two parallel-plate capacitors are constructed using dielectric materials with dielectric constants 3 and K2 = 5, as shown in Figure. Parallel-plates have the area A = 0.7 m². The distance is K1 d = 0.05 m. A potential difference of AV = 24 V is applied to the circuit. (a) Find the equivalent capacitance of the system. (b) Find the potential AV1. (E,=8.85×10-12 C²/N×m²) K1 A/2 AV. K2 A/2 А d K2 K1 A/2 2d/3 d/3 A/2 d AV = 24 V -F-----

2) Two parallel-plate capacitors are constructed using dielectric materials with dielectric constants 3 and K2 = 5, as shown in Figure. Parallel-plates have the area A = 0.7 m². The distance is K1 d = 0.05 m. A potential difference of AV = 24 V is applied to the circuit. (a) Find the equivalent capacitance of the system. (b) Find the potential AV1. (E,=8.85×10-12 C²/N×m²) K1 A/2 AV. K2 A/2 А d K2 K1 A/2 2d/3 d/3 A/2 d AV = 24 V -F-----

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter20: Electric Potential And Capacitance

Section: Chapter Questions

Problem 81P

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Similar questions

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