2. 99 *0.053- 0.0524.7 TOO 8,9x10-2=(0.05247 ) X 0,05247 1.69x10-10- X. 1.3x10-5 4.88 14-4.88=9.1 pHs Tog

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The concentration of Mg2+ in seawater is 0.053 M. At what pH will 99% of the Mg2+ be precipitated as the hydroxide salt? (Ksp for Mg(OH)2 = 8.9 ✕ 10−12. Assume that all solutions are at 25°C.)

 

I have tried solving for the pOH and then subtracting that from 14 to find the pH, but it is wrong everytime.  I don't understand where I'm going wrong.

2.
99
*0.053- 0.0524.7
TOO
8,9x10-2=(0.05247
) X
0,05247
1.69x10-10- X.
1.3x10-5
4.88
14-4.88=9.1
pHs
Tog
Transcribed Image Text:2. 99 *0.053- 0.0524.7 TOO 8,9x10-2=(0.05247 ) X 0,05247 1.69x10-10- X. 1.3x10-5 4.88 14-4.88=9.1 pHs Tog
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