2. A 0.5520 g of potassium hydrogen phthalate, KHCH&O4, a monoprotic weak acid, takes 24.90 mL of NaOH solution to reach the equivalence point. a. What is the molarity of the NaOH? b. Then, the base was used to analyze an unknown acid. It required 30.20 ml of the base to reach the equivalence point using 1.100 grams of the unknown. Calculate the equivalent weight of the unknown acid. C. If the unknown is prepared as KHP plus impurity, calculate the % of KHP in the unknown.

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter14: Equilibria In Acid-base Solutions
Section: Chapter Questions
Problem 74QAP: Fifty cm3 of 1.000 M nitrous acid is titrated with 0.850 M NaOH. What is the pH of the solution (a)...
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2. A 0.5520 g of potassium hydrogen phthalate, KHC&H&O4, a monoprotic weak acid, takes 24.90 ml of
NaOH solution to reach the equivalence point.
a. What is the molarity of the NaOH?
b. Then, the base was used to analyze an unknown acid. It required 30.20 ml of the base to reach
the equivalence point using 1.100 grams of the unknown. Calculate the equivalent weight of
the unknown acid.
c. If the unknown is prepared as KHP plus impurity, calculate the % of KHP in the unknown.
Transcribed Image Text:2. A 0.5520 g of potassium hydrogen phthalate, KHC&H&O4, a monoprotic weak acid, takes 24.90 ml of NaOH solution to reach the equivalence point. a. What is the molarity of the NaOH? b. Then, the base was used to analyze an unknown acid. It required 30.20 ml of the base to reach the equivalence point using 1.100 grams of the unknown. Calculate the equivalent weight of the unknown acid. c. If the unknown is prepared as KHP plus impurity, calculate the % of KHP in the unknown.
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