I need help 2. A 600 g spaghetti ball moving to the right at 2 m/s collides with an 800 g meatballat rest. After the collision, the 600 g ball is deflected at an angle of 37° above itsoriginal direction at a rate of 0.5 m/s. What is the magnitude and direction of the800 g meatball's velocity?

Name: I need help 2. A 600 g spaghetti ball moving to the right at 2 m/s col
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Description: I need help 2. A 600 g spaghetti ball moving to the right at 2 m/s collides with an 800 g meatballat rest. After the collision, the 600 g ball is deflected at an angle of 37° above itsoriginal direction at a rate of 0.5 m/s. What is the magnitude and

Answered: 2. A 600 g spaghetti ball moving to the…

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter8: Linear Momentum And Collisions

Section: Chapter Questions

Problem 31PE: A 0.240-kg billiard ball that is moving at 3.00 m/s strikes the bumper of a pool table and bounces...

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I need help

2. A 600 g spaghetti ball moving to the right at 2 m/s collides with an 800 g meatball
at rest. After the collision, the 600 g ball is deflected at an angle of 37° above its
original direction at a rate of 0.5 m/s. What is the magnitude and direction of the
800 g meatball's velocity?

Expert Solution

Step 1:- Concepts and formulas Used

Solution:-

1) According to the laws of conservation of Linear momentum, the linear momentum of the system remains conserved.

Along X-direction,

P_x,initial= P_x,final

where, P_x,initial= sum of the momentum along X- direction initially(before collision)

P_x,final = sum of momentum along X-direction, finally( after collision)

Similarly, Along Y-direction, we have

P_y,initial= P_y,final

where, P_y,initial= total momentum along Y-direction before collision

P_y,final = total momentum along Y-direction after collision

2) The momentum of an object moving with velocity v is given by

P = mv

here, m = mass of object

v = velocity of object

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