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- Using a block encoding scheme with encoding matrix ?=⌊3 5⌋ 23 a) Encrypt block (M Q) by listing all the steps b) Decrypt the encoded block; also, by listing all the stepsEncrypt and decrypt using the cipher, but in CBC mode. Recall that you can convert hexadecimal digits to binary to do the XOR operation. Encrypt the 4-block message fea1 using the above block cipher in CBC mode with an IV of 6 (0110 in binary). Decrypt the ciphertext db70 using the above cipher in CBC mode with an IV of 6.5. In the RSA system with p = 101, q = 103, and k = 1249, determine the public key(a, n), and encrypt the message M = 2.
- 2. Encrypt the following message using RSA cryptosystem. Message : THIS , with n=2633 and e=29.Use the RSA cipher with public key n = 713 = 23 · 31 and e = 43 to encode the messages HELP into their numeric equivalents and encrypt them. Performs all step. Use pencil and paper to write the answer. show your work as well.Question 1 :a) Generate the public private key pairs for Bob using the following values Bob P = 19Q = 13b) Encrypt the message “Network” using public key of Bob and then decrypt the message to get the plain text back
- 44. Using data p=3, q=11, n=pq, d=7 in RSA algorithm find the cipher text of the given plain text SUZANNE a. BUTAEEZ b. SUZANNE c. XYZABCD d. ABCDXYZSuppose that the encryption function mod 26, and , encrypt the letter “F” by “A”. Use the function to decrypt the message “ZSVXO”Encrypt the 12-bit plaintext 101010100111 using Simplified B-DES and the 9-bit key K = 010001111. This is a non-computer problem and you need to show all the steps of the encryption process
- There are other modes of block cipher besides the ones (OFB,CFB,CTR). One of these modes is named Plaintext Block Chaining (PBC) Mode. On the encryption side, the following is executed to obtain the nth ciphertext: Cn := Ek(Mn)XOR Mn-1. Suppose that we need to encrypt M1; : : : ;M5 using the PBC mode. Show the explicit formulas to obtain C1; : : : ;C5. What do you need to use for M0? Also, show the steps on the decryption side to obtain M1; : : : ;M5.The following text is encoded using Caesar cipher "Zbudhf" find the key and the corresponding plaintext.1. Let M be the plaintext message M = MALAYSIA and the private key, K = ISSOGOOD a) Using the expansion P-box (table is provided below), show the plaintext output of this process. b) For the key: Using the key permutation table (provided below), show the output of this conversion process.