2. A trench mortar fires a shell at angle of 30° with the horizontal with an initial velocity of 500 m/s. (See the diagram.) Find a) its range, R; b) the highest point reached, and c) time before it returns to the same level. Solution: Given: a) R = R = b) H= V₁² sin 20 g H = Vo²sin²0 2g tt = Vo = 0 = 2V0 sin A 2( ) sin 2( 9.8 m/s² _)²sin²( 2(9.8) sin( 9.8 m/s² y Vo R h x

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter3: Motion In Two Dimensions
Section: Chapter Questions
Problem 42P: A landscape architect is planning an artificial waterfall in a city park. Water flowing at 1.70 m/s...
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Upvote will be given! Write the solutions legibly. Follow the instructions carefully.

The finals answers should be:

a. R = 22,092.48 m

b. H = 3,188.78 m   

c.  tt = 51.02 sec

2. A trench mortar fires a shell at angle of 30° with the horizontal with an initial velocity of 500 m/s. (See the
diagram.) Find a) its range, R; b) the highest point reached, and c) time before it returns to the same level.
Solution: Given:
a) R =
R =
b) H=
V₁² sin 20
g
H =
Vo²sin²0
2g
tt =
Vo =
0 =
2V0 sin
A
2(
) sin 2(
9.8 m/s²
_)²sin²(
2(9.8)
sin(
9.8 m/s²
y
Vo
R
h
x
Transcribed Image Text:2. A trench mortar fires a shell at angle of 30° with the horizontal with an initial velocity of 500 m/s. (See the diagram.) Find a) its range, R; b) the highest point reached, and c) time before it returns to the same level. Solution: Given: a) R = R = b) H= V₁² sin 20 g H = Vo²sin²0 2g tt = Vo = 0 = 2V0 sin A 2( ) sin 2( 9.8 m/s² _)²sin²( 2(9.8) sin( 9.8 m/s² y Vo R h x
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