2. A triangular gate having a horizontal base 4 ft. long and an altitude of 6ft is inclined 45° from the horizontal with vertex pointing upward. The base of the gate is 8 ft below the surface of the liquid, which has a specific gravity of 0.82. What normal force, P must be applied at the vertex of the gate to open it, neglecting the weight of the gate. gate 45° -hinged

2. A triangular gate having a horizontal base 4 ft. long and an altitude of 6ft is inclined 45° from the horizontal with vertex pointing upward. The base of the gate is 8 ft below the surface of the liquid, which has a specific gravity of 0.82. What normal force, P must be applied at the vertex of the gate to open it, neglecting the weight of the gate. gate 45° -hinged

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter8: Centroids And Distributed Loads

Section: Chapter Questions

Problem 8.121P: One side of the container has a 03-m square door that is hinged at its top edge. If the container is...

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HYDROSTATIC FORCE ON PLANE SURFACE

Please show substitution and please make it easy to understand if handwritten. Also the final answer should be in KN. THANKYOU!!!

And how is inertia given by I = bd^3/36. Isn't it I = bd^3/12? THANKS!

2.
A triangular gate having a horizontal base 4 ft. long and an altitude of 6ft is inclined
45° from the horizontal with vertex pointing upward. The base of the gate is 8 ft below the
surface of the liquid, which has a specific gravity of 0.82. What normal force, P must be
applied at the vertex of the gate to open it, neglecting the weight of the gate.
gate
45°
hinged

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