2. An electric field (E=4.5N/C) passes through a flat surface area (0.30 m) with an angle of 45°. What will be the magnitude of the electric flux? 3. A closed surface which encloses a charge has an electric flux of 15.8N.m, 2 What is the magnitude of the charge?

Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter24: Gauss’s Law
Section: Chapter Questions
Problem 24.48AP: Consider a plane surface in a uniform electric field as in Figure P24.48, where d = 15.0 cm and =...
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number 2 and 3 only

Problem Solving:
1. An electric charge inside a sphere (r=0.81m) has a magnitude of
+4.8x10-18C. Find the electric flux through this surface.
2. An electric field (E=4.5N/C) passes through a flat surface area (0.30 m)
with an angle of 45°. What will be the magnitude of the electric flux?
3. A closed surface which encloses a charge has an electric flux of 15.8M.m,
What is the magnitude of the charge?
Transcribed Image Text:Problem Solving: 1. An electric charge inside a sphere (r=0.81m) has a magnitude of +4.8x10-18C. Find the electric flux through this surface. 2. An electric field (E=4.5N/C) passes through a flat surface area (0.30 m) with an angle of 45°. What will be the magnitude of the electric flux? 3. A closed surface which encloses a charge has an electric flux of 15.8M.m, What is the magnitude of the charge?
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