2. Binomial Experiment: A sleep study determines that one in five adults say they have no trouble sleeping at night. You randomly select seven adults and ask each if they have no trouble sleeping. Let X be the number of people who have no trouble sleeping at night. Determine if this is a binomial problem. a. 1. 2. 3. X~Binomial( n= p = b. Find the probability distribution table and draw the probability histogram for X. 40 P(x) 0. 0.20971520 0.36700160 P(x) 30 1 0.27525120 20 3. 0.11468800 4 0.02867200 .10 0.00430080 6. 0.00035840 0.00001280 0 1 2 3 4 5 6 7 7. c. Find the probability that at least one has no trouble sleeping. P( X )= d. Find the probability that at most 2 have no trouble sleeping. P( X ): e. Find the probability that more than 4 have no trouble sleeping. P(X _) ES<2> f. Find u and a for this distribution mean u st. dev a=

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter2: The Integers
Section2.7: Introduction To Coding Theory (optional)
Problem 7E
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Question
Page
7
> of 8
ZOOM +
X~Binomial( n=
b. Find the probability distribution table and draw the probability histogram for X.
40
P(x)
0.20971520
0.36700160
P(x) 30
0.27525120
3.
0.11468800
20
4
0.02867200
0.00430080
.10
6.
0.00035840
7
0.00001280
3
4
6.
c. Find the probability that at least one has no trouble sleeping. P( X
_) =
d. Find the probability that at most 2 have no trouble sleeping. P( X.
e. Find the probability that more than 4 have no trouble sleeping. P( X
f. Find uy and o, for this distribution:
Interpretation: 4, for the distribution tells us:
If seven random adults were selected over and over again, on average, we would expect
mean u
st. dev o=
out of every seven to
number
units
have the counted characteristic
Transcribed Image Text:Page 7 > of 8 ZOOM + X~Binomial( n= b. Find the probability distribution table and draw the probability histogram for X. 40 P(x) 0.20971520 0.36700160 P(x) 30 0.27525120 3. 0.11468800 20 4 0.02867200 0.00430080 .10 6. 0.00035840 7 0.00001280 3 4 6. c. Find the probability that at least one has no trouble sleeping. P( X _) = d. Find the probability that at most 2 have no trouble sleeping. P( X. e. Find the probability that more than 4 have no trouble sleeping. P( X f. Find uy and o, for this distribution: Interpretation: 4, for the distribution tells us: If seven random adults were selected over and over again, on average, we would expect mean u st. dev o= out of every seven to number units have the counted characteristic
Page <
> of 8
7
2. Binomial Experiment: A sleep study determines that one in five adults say they have
no trouble sleeping at night. You randomly select seven adults and ask each if they
have no trouble sleeping.
Let X be the number of people who have no trouble sleeping at night. Determine if
this is a binomial problem.
a.
1.
2.
3.
4.
X~Binomial ( n3=
b. Find the probability distribution table and draw the probability histogram for X.
.40
P(x)
0.20971520
30
1
0.36700160
P(x)
0.27525120
20
0.11468800
4
0.02867200
.10
0.00430080
6.
0.00035840
0.00001280
1
3.
4
6.
c. Find the probability that at least one has no trouble sleeping. P( X.
_)=.
=s<2>
d. Find the probability that at most 2 have no trouble sleeping. P( X
=s<2>
e. Find the probability that more than 4 have no trouble sleeping. P( X.
-) =.
f. Find u and a for this distribution:
mean u
st. dev a=
Transcribed Image Text:Page < > of 8 7 2. Binomial Experiment: A sleep study determines that one in five adults say they have no trouble sleeping at night. You randomly select seven adults and ask each if they have no trouble sleeping. Let X be the number of people who have no trouble sleeping at night. Determine if this is a binomial problem. a. 1. 2. 3. 4. X~Binomial ( n3= b. Find the probability distribution table and draw the probability histogram for X. .40 P(x) 0.20971520 30 1 0.36700160 P(x) 0.27525120 20 0.11468800 4 0.02867200 .10 0.00430080 6. 0.00035840 0.00001280 1 3. 4 6. c. Find the probability that at least one has no trouble sleeping. P( X. _)=. =s<2> d. Find the probability that at most 2 have no trouble sleeping. P( X =s<2> e. Find the probability that more than 4 have no trouble sleeping. P( X. -) =. f. Find u and a for this distribution: mean u st. dev a=
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