2. Determine the potential and kinetic energy for each position. (100 meters, 30meters, 60 meters, O meter)KE=0 JPE=35 000 JKE=KE=PE=PE-100 m60 mKE-KEPE>30 mPE=

At 100 m KE = 0 PE = 35000 J = m×10×100 m = 35 kg Now, At 30 m PE = 35×10×30 = 10500 J KE =…

Answered: 2. Determine the potential and kinetic…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter6: Energy Of A System

Section: Chapter Questions

Problem 33P: A 0.600-kg particle has a speed of 2.00 m/s at point and kinetic energy of 7.50 J at point . What...

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2. Determine the potential and kinetic energy for each position. (100 meters, 30 meters, 60 meters, O meter) KE=0 J PE=35 000 J KE= KE= PE= PE- 100 m 60m KE- KE- PE 30 m PE=