2. Given the following data of the slip-critical tension connection shown with 22mm-diameter bolts in standard holes with threads excluded from shear planes. Considering plates only, compute the design tensile strength (LRFD) and the allowable tensile strength (ASD) using NSCP 2015 (Fy=248 MPa, Fu-400 Mpa) P/2 P/2 350mm 40mm 75 100 100 75 75mm 75mm 350 x 12 mm 40mm 350 x 22 mm P Activat Go to Se

2. Given the following data of the slip-critical tension connection shown with 22mm-diameter bolts in standard holes with threads excluded from shear planes. Considering plates only, compute the design tensile strength (LRFD) and the allowable tensile strength (ASD) using NSCP 2015 (Fy=248 MPa, Fu-400 Mpa) P/2 P/2 350mm 40mm 75 100 100 75 75mm 75mm 350 x 12 mm 40mm 350 x 22 mm P Activat Go to Se

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Please answer it asap for an upvote. Thankyou. An A992 steel plate (12mm thick, in yellow) is connected to another A992 steel plate (12mm thick, in gray) using four bolts having a diameter of 33mm. If "x" makes the net width along bolts 1-2-4 equal to that of the net width along bolts 1-2-3-4; Compute the design tensile fracture capacity using the most critical net area (in kN).
For the connection shown in the accompanying illustration, Pu = 360 k and Pa = 260 k. Determine by LRFD and ASD the number of 7/8-in A490 bolts required for a bearing-type connection,using A36 steel.Threads are excluded from shear plane.
Plz, solve this problem as detail as you can? Steel Structure Design a concentrically loaded bolted connection with the following given information. Also verify your design and draw s sketch showing final layout of the connection. Size and type of bolts: 3/4-in A325 (Group A) bolts in standard-size holes with threads excluded from the shear plane in a bearing-type connection shown in figure 1. Use Fu= 58 ksi and assume edge distances to be 2 in and the distance center-to-center of holes to be 3 in, Assume that deformation at bolt holes is a design consideration. Pu = 345 k using LRFD
Calculate the maximum tensile load, Ta or Tu of the connection shown in Figure 7. Theconnection consists of two 3/8" plates fastened to each side of one 13/16" plate.Assume 7/8" diameter bolts and standard punched holes. Use A36 steel. The plate is 13” wide. Note: Be sure to check all failure modes; bolt failure modes, and member failure modes(including block shear)
A C15x40 channel section is bolted to a gusset plate is used to resist a tensile loadPu =313 k. The bolts are 3/4 inch  diameter bolts A325 N (Group A, N Type) used insingle shear to resist this load. The bolts are to be symmetric and arranged in 3 rows.1) Determine the number of bolts needed for this connection. Draw a detailshowing how the bolts are arranged and showing spacing and edge distances onthis connection. Assume edge distance Le = 1.75db , use Le to nearest 1/4 in.2) If the connection is to be replaced by a fillet welded connection with transversewelds only along the channel web, determine the required fillet size to thenearest 16th of an inch.
The design shear strength phi rnv of one A325 X-bolt, 1 1/8 inch in diameter (Group A, X type) in double shear is equal to: Group of answer choices 112 kips 125 kips 74.2 kips 101 kips
a rivet lap joint is shown. The rivets used have allowable shear strength equal to 533 MPA with diameter of 16mm. The steel plate has a yield strength equal to 275 MPa and ultimate strength equal to 340 mpa; 300 mm wide and 16 mm thick. Determine the safest value of P that the connection can resist. Use NSCP, assume additional 1.6mm for the rivet hole. Neglect block shear
Two plates each with thickness t = 5 mm are bolted together with 6 - 22 mm diameter bolts forming a lap connection. Plate (A36): Fy = 248 Mpa FU = 400 MPa bolts are A325 in standard holes with threads excluded from shear planes. Considering Tension Rupture, compute the the design strength for LFRD. Use NSCP 2015
Given W 16x36 section as shown below (Fy = 50ksi, Fu= 65ksi). The holes are 3/4 inch in diameter. The connection is bolted at the web only. Assume x=0.76 inch, determine... 3. The Tensile strength Tn (LRFD) neglecting block shear failure mode.
An A36 steel plate (12mm thick, in yellow) is connected to another A36 steel plate (12mm thick, in gray) using four bolts having a diameter of 33mm. If "x" makes the net width along bolts 1-2-4 equal to that of the net width along bolts 1-2-3-4; Determine the most critical net area (in mm2). Please answer this asap. For upvote. Thank you very much
Two steel plate tension members have been connected using 0.72 inch diameter bolts arranged in an equally-spaced 9 by 3 rectangular formation. Both plates have a thickness equal to 1/3 in. Take shear fracture stress as 51.2 ksi, clear distance for each edge bolt as 0.12 in, and the clear distance for the other bolts as 1.072 in. a)Sketch the connection showing all the details and measurements with units. b)Find the maximum allowable service dead load and live load assuming live load is half as much as dead load. Consider ASD.
Steel design. The butt connection shows 8-22mm diameter A325 bolts spaced as follows S1= 40m ,S2= 80mm, S3=50 mm, S4= 100mm Thickness of plates : t1= 16mm , t2= 12mm Steel strength and stresses are: Yield Strength,Fy=248 MPa Ultimate strength,Fu=400MPa Allowable tensile stress on the gross area = 148MPa Allowable tensile stress on the net area= 148MPa Bearing stress on projected area,Fp=600MPa Allowable bolt shear stress,Fv=120MPa