2. In the titration of 50.0 mL of 1.0 M methylamine, CH₂NH₂ (K-4.4x10), with 0.50 M HCl, calculate the pH at the half-equivalence point, i.e. when [CH3NH₂]-[CH₂NH₂]. (

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter16: Reactions Between Acids And Bases
Section: Chapter Questions
Problem 16.53QE
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2. In the titration of 50.0 mL of 1.0 M methylamine, CH3NH2 (Ks-4.4x10), with 0.50 M HCl, calculate the pH
at the half-equivalence point, i.e. when [CH₂NH₂]-[CH₂NH₂¹]. (
Transcribed Image Text:2. In the titration of 50.0 mL of 1.0 M methylamine, CH3NH2 (Ks-4.4x10), with 0.50 M HCl, calculate the pH at the half-equivalence point, i.e. when [CH₂NH₂]-[CH₂NH₂¹]. (
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