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2.One parent is homozygous dominant and the other heterozygous dominant forchin fissure gene.NOTE: chin fissure is a dominant trait Fsmooth chin is a recessive trait fMom's genotype?A. Probability that child will havea chin fissure?Dad's genotype?B. Probability that child will behomozygous dominant for a chinfissure?C. Probability that child will beheterozygous dominant for a chinfissure?D. Probability that child will behomozygous recessive for asmooth chin?7

Question
2.
One parent is homozygous dominant and the other heterozygous dominant for
chin fissure gene.
NOTE: chin fissure is a dominant trait F
smooth chin is a recessive trait f
Mom's genotype?
A. Probability that child will have
a chin fissure?
Dad's genotype?
B. Probability that child will be
homozygous dominant for a chin
fissure?
C. Probability that child will be
heterozygous dominant for a chin
fissure?
D. Probability that child will be
homozygous recessive for a
smooth chin?
7
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2. One parent is homozygous dominant and the other heterozygous dominant for chin fissure gene. NOTE: chin fissure is a dominant trait F smooth chin is a recessive trait f Mom's genotype? A. Probability that child will have a chin fissure? Dad's genotype? B. Probability that child will be homozygous dominant for a chin fissure? C. Probability that child will be heterozygous dominant for a chin fissure? D. Probability that child will be homozygous recessive for a smooth chin? 7

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Step 1

The allele combination of a gene present in an organism determines the genotype and phenotype. The genotype is the specific allele combination of a gene and the physical manifestation of the genotype is known as phenotype. An organism with two copies of same dominant allele is homozygous dominant and the organism with two copies of same recessive alleles is homozygous recessive. Heterozygous genotype consists of two different alleles of a gene.

Step 2
It is given that one parent is homozygous dominant and other is heterozygous dominant for
the chin fissure gene
Case Considering that father is homozygous dominant and mother is heterozygous
dominant, the genotype of father is FF and the genotype of mother is Ff.
Where F is the dominant allele and f is the recessive allele. The probability can be estimated
by the punnett square
Male/Female
F
f
FF
Ff
FF
Ff
Case 2: Considering that father is heterozygous dominant and mother is homozygous
dominant, the genotype of father is Ff and the genotype of mother is FF. The probability can
be estimated by the punnett square
Male/ Female
F
F
FF
FF
Ff
Ff
f
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Image Transcriptionclose

It is given that one parent is homozygous dominant and other is heterozygous dominant for the chin fissure gene Case Considering that father is homozygous dominant and mother is heterozygous dominant, the genotype of father is FF and the genotype of mother is Ff. Where F is the dominant allele and f is the recessive allele. The probability can be estimated by the punnett square Male/Female F f FF Ff FF Ff Case 2: Considering that father is heterozygous dominant and mother is homozygous dominant, the genotype of father is Ff and the genotype of mother is FF. The probability can be estimated by the punnett square Male/ Female F F FF FF Ff Ff f

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