2. Otherwise, search recursively by comparing K with the element located at [n/4]. If it equal, then youre done. If its smaller then continue with the sublist to the left of n/4 3. If, on the other hand, its bigger than n/4|, then compare it with the element located [3n/4] and do exactly as you did in (2) i.e. you either found it at 3n/4] or you contir with one of the sublists that are on the left or right of [3n/4]. (a) Write the pseudocode of the above describe search algorithm. (b) Set up a recurrence desginating a lower bound on the number of key comparisons. (c) Set up a recurrence designating an upper bound on the number of key comparisions.

2. Otherwise, search recursively by comparing K with the element located at [n/4]. If it equal, then youre done. If its smaller then continue with the sublist to the left of n/4 3. If, on the other hand, its bigger than n/4|, then compare it with the element located [3n/4] and do exactly as you did in (2) i.e. you either found it at 3n/4] or you contir with one of the sublists that are on the left or right of [3n/4]. (a) Write the pseudocode of the above describe search algorithm. (b) Set up a recurrence desginating a lower bound on the number of key comparisons. (c) Set up a recurrence designating an upper bound on the number of key comparisions.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Consider the Sort-and-Count algorithm explained in section 5.3 of our text: "Counting Inversions"Suppose that the initial list is: 92 71 36 91 27 48 14 34 81 26 24 65 78 51 37 22 Sort-and-Count makes two recursive calls. The first recursive call inputs the first half of the initial list: 92 71 36 91 27 48 14 34 and returns the sorted version of the first half, as well as the number of inversions found in the first half (22). The second recursive call inputs the second half of the initial list: 81 26 24 65 78 51 37 22 and returns the sorted version of the second half, as well as the number of inversions found in the second half (19). Sort-and-Count then calls Merge-and-Count. To Merge-and-Count, Sort-and-Count passes the sorted versions of the two halves of the original list: 14 27 34 36 48 71 91 92, and 22 24 26 37 51 65 78 81 Merge-and-Count begins merging the two half-lists together, while counting…
design an algorithm to find all the common elements in two sorted lists of numbers. For example, for the lists 2, 5, 5, 5 and 2, 2, 3, 5, 5, 7, the output should be 2, 5, 5.What is the maximum number of comparisons your algorithm makes if the lengths of the two given lists are m and n, respectively?
A sequential search of a sorted list can halt when the target is less than a givenelement in the list. Define a modified version of this algorithm and state thecomputational complexity, using big-O notation, of its best-, worst-, and average-case performances. Using this template in python: def sequential_search(input_list, target):target_index = -1#TODO: Your work here# Return target_index. If not found, -1return target_indexif __name__ == "__main__":my_list = [1, 2, 3, 4, 5]print(sequential_search(my_list, 3)) # Correct Output: 2print(sequential_search(my_list, 0)) # Correct Output: -1
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Implement MSD string sorting using queues, as follows: Keep onequeue for each bin. On a first pass through the items to be sorted, insert each item intothe appropriate queue, according to its leading character value. Then, sort the sublistsand stitch together all the queues to make a sorted whole. Note that this method doesnot involve keeping the count[] arrays within the recursive method.
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