2. Rigid-Body in Equilibrium.A nonuniform beam 4.50 m long and weighing 1,000 N makes an angle of25.0° below the horizontal. It is held in position by a frictionless pivot at its upper right end and by a cable3.00 m farther down the beam and perpendicular to it. The center of gravity of the beam is 2.00 m downthe beam from the pivot. Lighting equipment exerts a 5,000-N downward force on the lower left end of thebeam.25.0°PivotCableCenter of gravityof the beam(i)(ii)(ii)Sketch the free-body diagram (FBD) of the beam with complete force labels.Determine the moment arm () of each force. Show complete solution. Put the results in a table.Determine the sign of the torque, based on the direction of rotation of the beam that is causedby each torque. Indicate these on your FBD.Indicate the signs of the torques in the table of results.Find the tension (T) in the cable and the horizontal and vertical components of the forceexerted on the beam by the pivot (Fpx and Fpy).(iv)

Answered: Image /qna-images/answer/5908b357-791a-4a24-9e7f-35153c5afd38.jpg

2. Rigid-Body in Equilibrium. A nonuniform beam 4.50 m long and weighing 1,000 N makes an angle of 25.0° below the horizontal. It is held in position by a frictionless pivot at its upper right end and by a cable 3.00 m farther down the beam and perpendicular to it. The center of gravity of the beam is 2.00 m down the beam from the pivot. Lighting equipment exerts a 5,000-N downward force on the lower left end of the beam.

2. Rigid-Body in Equilibrium. A nonuniform beam 4.50 m long and weighing 1,000 N makes an angle of 25.0° below the horizontal. It is held in position by a frictionless pivot at its upper right end and by a cable 3.00 m farther down the beam and perpendicular to it. The center of gravity of the beam is 2.00 m down the beam from the pivot. Lighting equipment exerts a 5,000-N downward force on the lower left end of the beam.

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter9: Statics And Torque

Section: Chapter Questions

Problem 18PE: In Figure 9.21, the cg of the pole held by the pole vaulter is 2.00 m from the left hand, and the...

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In Figure 9.21, the cg of the pole held by the pole vaulter is 2.00 m from the left hand, and the hands are 0.700 m apart. Calculate the force exerted by (a) his right hand and (b) his left hand. (c) If each hand supports half the weight of the pole in Figure 9.19, show that the second condition for equilibrium (net =0 ) is satisfied for a pivot other than the one located at the center of gravity of the pole. Explicitly show how you follow the steps in the Problem-Solving Strategy for static equilibrium described above. Figure 9.21 A pole vaulter is holding a pole horizontally with both hands. The center of gravity is to the left side of the vaulter.
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