2. Solve for the magnitude of the electric field of a point charge (straight line) given: 91 = +45µC 92 = -23 µC q3 = +41 Mc %3D %3D Solve for the magnitude of the electric field on the point charge next to qa if each point charges are separated by 0.89 m apart. Don't forget to draw a free-body diagram.

College Physics
10th Edition
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter15: Electric Forces And Electric Fields
Section15.3: Coulomb's Law
Problem 15.3QQ: A test charge of + 3 C is at a point P where the electric field due to other charges is directed to...
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Draw the Free body diagram with electric field direction and  Find the Magnitude and Direction of the now Resultant Vector. (Electric Field)

2. Solve for the magnitude of the electric field of a point charge (straight line) given:
91 = +45µC q2 = -23 µC 43 = +41 Mc
Solve for the magnitude of the electric field on the point charge next to qa if each
point charges are separated by 0.89 m apart.
Don't forget to draw a free-body diagram.
Transcribed Image Text:2. Solve for the magnitude of the electric field of a point charge (straight line) given: 91 = +45µC q2 = -23 µC 43 = +41 Mc Solve for the magnitude of the electric field on the point charge next to qa if each point charges are separated by 0.89 m apart. Don't forget to draw a free-body diagram.
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