2.) Striking a match stick on the matchbox involves the reaction of potassium chlorate and red phosphorus with the following equation: 10 KCIO3 (s) + 3 P4 (s) ---> 3 P4O10 (s) + 10 KCI (s) (A) How much reactant (KCIO3) will be needed to produce 105.8 g of P4O10? (B) How much reactant (P4) will be needed to produce 105. g of P4010? Molar Masses: 1 mole of KCIO3 = 122.55 grams of KCIO3 1 mole of P4 = 123.88 grams of P4 1 mole of P4O10 = 283.88 grams of P4010 Ratio: 10 mole of KCIO3 = 3 mole of P4010 3 mole of P4 = 3 mole of P4010
2.) Striking a match stick on the matchbox involves the reaction of potassium chlorate and red phosphorus with the following equation: 10 KCIO3 (s) + 3 P4 (s) ---> 3 P4O10 (s) + 10 KCI (s) (A) How much reactant (KCIO3) will be needed to produce 105.8 g of P4O10? (B) How much reactant (P4) will be needed to produce 105. g of P4010? Molar Masses: 1 mole of KCIO3 = 122.55 grams of KCIO3 1 mole of P4 = 123.88 grams of P4 1 mole of P4O10 = 283.88 grams of P4010 Ratio: 10 mole of KCIO3 = 3 mole of P4010 3 mole of P4 = 3 mole of P4010
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.93P: 4-93 Ammonia is prepared industrially by the reaction of nitrogen and hydrogen according to the...
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