2. The following are the Incremental fuel cost curves of two thermal generator units, IC₁= 0.2 P₁ + 50 IC2 = 0.24 P2 +40 The limits of the generators are as follows 20 MW Pg1 ≤ 150 MW 20 MW ≤ Pg2 ≤ 150 MW For a certain load demand P₁ AND P2 has been chosen such that dC₁ OMR = X dP₁ MWhr dC₂ OMR dP₂ MWhr a) Find the values of P1 & P2. b) If the generation are rescheduled to minimize the cost, Determine P2. = Y
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- electrical machines 3. 400 V 50 Hz, Y-connected, 6-pole synchronous generator per phase synchronous reactance 1.0 Ω at back power factor of 0.9 full load armature current 50 A, friction and wind losses 1.25 kW and core losses at 50Hz full load 1.0 kW and armature resistance and loss are neglected. The excitation current is adjusted so that the no-load output voltage is 400V. According to this; a) Calculate the rotation speed of the generator. b) find the terminal voltages at load with rated current at 0.8 back power factor and unit power factor . c) Calculate the voltage regulation of the generator for power coefficients of 0.8 back and 1.0.Terminal voltage of shunt G1 generator in idle operation is 500 V. The terminal voltage of the G1 generator drops to 470 V if it delivers a load current of 600 A. The idle operating voltage of the shunt G2 generator is 505 V. G2 generator terminal voltage drops to 470 V in case of 400 A load current. These two generators are connected in parallel to feed a load of 400 kW. Voltage-power characteristics of generators are linear. According to this; a. Draw the connection diagram given in the question. b. Obtain the network voltage and the powers of the generators. c. Calculate the current given by each generator to the load.380 V, 50 Hz, 2p = 6, star connected induction motor impedance in ohms per phase values:R1 = 0.3, X1 = j0.45, R2 = 0.15, X2 = j0.45, Xm = j15Its total mechanical losses are 500W. Core losses are negligible. For a rotor slip of 0.01 at rated voltage, calculate the following:1-rotor speed2-Input active power3-Stator copper losses4-air gap power5-Transferred power and Output power6-shaft moment7-efficiency
- N K © M =] v : @& docs.google.com/forms/d/¢ 2 Add file Q 1/ B) What is the work of Commutator . * &2, Add file Q 2) The following information is given for a 300-kW, 600-V, long-shunt compound generator : Shunt field resistance = 75 Q, armature resistance including brush resistance = 0.03 Q, commutating field winding resistance = 0.011Q, series field resistance = 0.012 Q, diverter resistance = 0.036 Q. When the machine is delivering full load, calculate the voltage and power generated by the armature * 2 Add file Q 3) A four pole aenerator havina - >A 6-phase ∆-connected 1600 V (line-to-line), 150 kW, 50 Hz, six-pole induction driveis used in an electric car. The drive has the following parameter values in Ω/phasereferred to the stator:R1 =0.334 Ω R2 =0.168 Ω Rm1 = 125 ΩX1 = 0.273 Ω X2 = 0.287 Ω Xm1 = 16.78 ΩThe total friction, windage, and core losses may be assumed to be constant at Prot =773 W, independent of load. For a slip value of s=0.015: b ) Compute the speed, output torque, power and stator current d) Calculate the efficiency when the motor is operated at rated voltage andfrequency. answer:b) n= 985 rpm; Torque T= 1.18 x104 Nm; Power= 1.22 x106 W; Stator current I = 175.72 /32.79° (d) Efficiency = 86.4%A 4-pole, 250V, 120kW, DC short shunt compound generator has the following parameters: Ra=0.015 Ω, Rse=0.01 Ω, Rf =125 Ω, flux per pole=3x10 maxwells, Speed=1000rpm, hysteresis loss=2.5kW, eddy current loss=1.5kW, total mechanical loss=5kW. At what speed and excitation does this generator needs to operate in order to maintain an overall efficiency of 88%. Note: Excitation needs to be adjusted with speed in order to generate the same emf
- Problem details: A 15 kW, 280V, 1200 rpm washing machine needs to be fed by a generator in your home. You have a friend in a generator manufacturer company. He gave you different options and as you’re studying in EE department, he asked you to choose the best one from those! The generator details are as shown Type of Generator: Series Armature resistance (Ω) = 0.8 Field resistance (Ω) = - Series Resistance (Ω) = 2.2 Hysteresis loss (kW) = 1.1 Eddy current loss (kW) = 1.7 Rotational loss (kW) = 1.2 Calculate the following things for each of the generator types: a) The generated voltage b) The field circuit voltage c) The developed torque d) The efficiency Also neatly draw the circuit diagram for all of them.A 4-pole, 250V, 120kW, DC short shunt compound generator has the following parameters: Ra=0.015 Ω, Rse=0.01 Ω, Rf =125 Ω, flux per pole=3x10^6 maxwells, Speed=1000rpm, hysteresis loss=2.5kW, eddy current loss=1.5kW, total mechanical loss=5kW. At what speed and excitation does this generator needs to operate in order to maintain an overall efficiency of 88%. Note: Excitation needs to be adjusted with speed in order to generate the same emf.DEGREE: BS Electrical Engineering COURSE/SUBJECT: AC Machines illustrate/draw the problem. Solving is optional, solved in previous post problem already PROBLEM: A three-phase, 3 KV, P=24, 50Hz, Y-connected slip ring IM has a rotor resistance of 0.015 ohm and a stand still reactance of 0.265 ohm per phase. Full load torque Is obtained al a speed of 245 rpm. Neglect stator impedance, Calculate (A) Ratio of Maximum Torque to Full load Torque (B) Speed at Maximum Torque
- The synchronous reactance of the direct-axis and quadrature-axis of a three-phase,40-pole, 50 Hz, 13,8 kV, salient-pole synchronous generator is 2,38 Ω and 1,33 Ωrespectively. The resistance of the star-connected stator is negligible. The load angle ofthe machine is 30°e and the excitation is set to induce an emf of 167%. Sketch the phasordiagram and calculate:(a) current(b) power(c) reluctance torque(d) the maximum load angle(e) the maximum power developedA 4 pole lap wound shunt generator delivers 200A at a terminal voltage of 220V. Ra and Rsh are 0.02Ω and 55Ω respectively. Neglecting brush drop, determine (i) armature current (ii) current per parallel path, (iii) generated voltage and (iv) Power developed.A 480 V, 60 Hz ,Delta Connected, Four Poles Synchronous Generator has A Direct Axis Reactance of 0.1 Ohm, and Quadrature Axis Reactance of 0.075 Ohm .Its Armature Resistance May be Neglected. At Full Load, This Generator Supplied 1200 A , at A Power Factor Of 0.8 Lagging. 1-Find The Internal Generated Voltage (E), of This Generator at Full that it has A Cylindrical Rotor of Reactance Xd ( Xd =Xs). Load . Assuming 2- Find the Internal Generated Voltage E, of this Generator at Full Load. Assuming It has Salient Pole Rotor.