2. The intracellular concentration of glucose-6-phosphate and fructose-6-phosphate are measured inside the cell of a patient and the following values were obtained: [glucose-6-phosphate] = 8 x 10-5 M [fructose-6-phosphate] = 1.5 x 10-5 M %3D %3D Is this reaction at equilibrium?. What is the value of Q?. What do you predict the sign for AG will be? Calculate AG for this reaction..
2. The intracellular concentration of glucose-6-phosphate and fructose-6-phosphate are measured inside the cell of a patient and the following values were obtained: [glucose-6-phosphate] = 8 x 10-5 M [fructose-6-phosphate] = 1.5 x 10-5 M %3D %3D Is this reaction at equilibrium?. What is the value of Q?. What do you predict the sign for AG will be? Calculate AG for this reaction..
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter16: Thermodynamics
Section: Chapter Questions
Problem 48E: At mom temperature, the equilibrium constant (Kw) for the self-ionization of water is 1.001014....
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If the value of ∆G is negative will represent the reaction conditions are favorable. If the value of ∆G is positive will represent the reaction conditions are unfavorable. When the reaction is an equilibrium value of ∆G is zero. Unit of ∆G is kJ per mol.
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