2. The number of patients visiting an emergency room during the graveyard shift (11:00pm-7:00pm), denoted by the random variable X, has the following probability distribution: 1 2 3 4 5 6 P(X=x) .05 .20 .25 .20 .10 .15 .05 a. Find the probability there will be 3 or more emergency room patients during a randomly selected 8-hour graveyard shift. b. Find the probability there will be an even number of patients.

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Counting And Probability
Section9.3: Binomial Probability
Problem 2E: If a binomial experiment has probability p success, then the probability of failure is...
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Please answer d and e
2. The number of patients visiting an emergency room during the
graveyard shift (11:00pm-7:00pm), denoted by the random variable X, has the
following probability distribution:
1
2
3
4
5
P(X=x)
.05
.20
.25
.20
.10
.15
.05
a. Find the probability there will be 3 or more emergency room patients during a
randomly selected 8-hour graveyard shift.
b. Find the probability there will be an even number of patients.
c. Find the probability there will be at least 2 but not more than 5 patients.
d. Find the probability there will be less than 2 patients.
e. How do you suppose the probability distribution above was obtained?
Transcribed Image Text:2. The number of patients visiting an emergency room during the graveyard shift (11:00pm-7:00pm), denoted by the random variable X, has the following probability distribution: 1 2 3 4 5 P(X=x) .05 .20 .25 .20 .10 .15 .05 a. Find the probability there will be 3 or more emergency room patients during a randomly selected 8-hour graveyard shift. b. Find the probability there will be an even number of patients. c. Find the probability there will be at least 2 but not more than 5 patients. d. Find the probability there will be less than 2 patients. e. How do you suppose the probability distribution above was obtained?
Expert Solution
Step 1

Given probability distribution:

X 0 1 2 3 4 5 6
P(X=x) 0.05 0.20 0.25 0.20 0.10 0.15 0.05
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