
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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•2. The relative frequency distribution of the number of TVs sold in a day in a department store in the last year is as follows:•Number of TV sold01234•Relative Frequency (probability) 0.10.150.450.2 0.1• Compute the
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- The high temperature X (in degrees Fahrenheit) on January days in Columbus, Ohio, varies according to the Normal distribution with mean 21 and standard deviation 10. If a January day in Columbus is randomly selected, what is the probability that the high temperature is between 15 and 25 degrees?arrow_forwardTo become an actuary, it is necessary to pass a series of 10 exams, including the most important one, an exam in probability and statistics. An insurance company wants to estimate the mean score on this exam for actuarial students who have enrolled in a special study program. They take a sample of 8 actuarial students in this program and find the mean of the sample is 6.0 with standard deviation of the sample 2.0. This sample will be used to calculate a 95% confidence interval for the mean score for actuarial students in the special study program. A 95% confidence interval for the mean score of actuarial students in the special program is from ________ to ________. Question 17 options: 1) 3.52 to 8.47 2) 4.69 to 7.31 3) 4.66 to 7.34 4) 4.33 to 7.67arrow_forwardSuppose the heights of students in a class follows normal distribution. The mean is 66 inches and the standard deviation is 5 What is the probability that a randomly selected student height is above 69 inches? What is the probability that the height will fall in between 45-54 inches? Which of the following intermediate step is involved in finding probability that a randomly selected student height is more than 70 inches?arrow_forward
- A bus heading to university is always scheduled to arrive at a certain bus stop at 7:30am. The difference between the actual arrival time and 7:30am is normally distributed with mean 0 and standard deviation of 2 minutes.A student who always has a class at 8am decided to be at the bus stop at 7:28am in order to try to guarantee catching this bus. What is the probability that the student will catch the bus on any particular day?Probability = What is the probability that the student will catch the bus at least 4 times out of 5 days?Probability =arrow_forwardThe mean cholesterol levels of women age 45-59 in Ghana, Nigeria, and Seychelles is 5.1 mmol/l and the standard deviation is 1.0 mmol/l. AsSume that cholesterol levels are normally distributed and a random sample of 21 women are selected. It is possible with rounding for a probability to be 0.0000.arrow_forwardIn 2000, the average height of a woman aged 20-74 years was 64 inches with an increase of approximately 1 inch from 1960. Suppose the height of a woman is normally distributed with a standard deviation of two inches. • What is the probability that a randomly selected woman in this population is between 64 inches and 70 inches? • What is the probability that one woman selected at random from this population all exceed 70 inches? O a. NONE Ob.0.9973, 6.0042 x 10-9 Oc 0.0973, 0.0228 Od.0.4987, 0.0013arrow_forward
- Suppose that the commuting time on a particular train is uniformly distributed between 35 and 55 minutes. What is the standard deviation of the commuting time?arrow_forwardThe high temperature xx (in degrees Fahrenheit) on January days in Columbus, Ohio, varies according to the Normal distribution with mean 20 and standard deviation 7. What is the probability that the temperature on a random January day in Columbus is below 10 degrees?arrow_forwardSuppose that the number of customers who enter a supermarket each hour is normally distributed with a mean of 650 and a standard deviation of 230. The supermarket is open 15 hours per day. What is the probability that the total number of customers who enter the supermarket in one day is greater than 10400? (Hint: Calculate the average hourly number of customers necessary to exceed 10400 in one 15-hour day.) Probability =arrow_forward
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