2.) This question builds somewhat on top of the previous question. Instead of adding single bits at a time, let's scale this up to two bits. This is visually represented below: + Cout R1 RO A1 A0 B1 BO For this problem, you are given a carry-in bit `Cin`, as well as the operands `A` and `B`, just as before. However, A and `B` are now two bits apiece, with `A0` holding the bit at position 0 and `Al` holding the bit at position 1, and so on. This still produces `R` as a result, though the result is now two bits large, with `R0 holding the result value at position 0, and `R1 holding the result value at position 1. Cout holds the carry-out bit, as before. As before, fill in the table below. Note the ordering of the inputs. The first few have already been completed for you. Cin Al B1 A0 B0 | Cout R1 RO | 0 | 0 2a) 0 2b) 0 0 2c) 0 2d) 0 2e) 0 2f) 0 2g) 0 2h) 0 2aa) 1 2ab) 1 2ac) 1 2ad) 1 2ae) 1 2af) 1 OOO O 0 0 0 21) 0 1 2j) 0 1 2k) 0 1 21) 0 1 2m) 0 1 2n) 0 1 20) 0 1 2p) 0 1 0 0 2q) 1 2r) 1 2s) 1 2t) 1 2u) 1 2v) 1 2w) 1 2x) 1 2y) 1 2z) 1 Cin 0 0 0 0 0 1 0 0 1 0 оооооо 1 1 1 1 1 1 1 1 0 1 0 1 1 0 1 0 1 1 1 0 1 1 1 0 0 0 0 0 1 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1 0 1 0 1 0 1 0 1 0 1 0 1 0 0 0 1 1 1 0 1 1 1 нноооонннноооон OOTI онноонноонноо COO | 0 0 0 1 1 C 0
2.) This question builds somewhat on top of the previous question. Instead of adding single bits at a time, let's scale this up to two bits. This is visually represented below: + Cout R1 RO A1 A0 B1 BO For this problem, you are given a carry-in bit `Cin`, as well as the operands `A` and `B`, just as before. However, A and `B` are now two bits apiece, with `A0` holding the bit at position 0 and `Al` holding the bit at position 1, and so on. This still produces `R` as a result, though the result is now two bits large, with `R0 holding the result value at position 0, and `R1 holding the result value at position 1. Cout holds the carry-out bit, as before. As before, fill in the table below. Note the ordering of the inputs. The first few have already been completed for you. Cin Al B1 A0 B0 | Cout R1 RO | 0 | 0 2a) 0 2b) 0 0 2c) 0 2d) 0 2e) 0 2f) 0 2g) 0 2h) 0 2aa) 1 2ab) 1 2ac) 1 2ad) 1 2ae) 1 2af) 1 OOO O 0 0 0 21) 0 1 2j) 0 1 2k) 0 1 21) 0 1 2m) 0 1 2n) 0 1 20) 0 1 2p) 0 1 0 0 2q) 1 2r) 1 2s) 1 2t) 1 2u) 1 2v) 1 2w) 1 2x) 1 2y) 1 2z) 1 Cin 0 0 0 0 0 1 0 0 1 0 оооооо 1 1 1 1 1 1 1 1 0 1 0 1 1 0 1 0 1 1 1 0 1 1 1 0 0 0 0 0 1 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1 0 1 0 1 0 1 0 1 0 1 0 1 0 0 0 1 1 1 0 1 1 1 нноооонннноооон OOTI онноонноонноо COO | 0 0 0 1 1 C 0
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
Transcribed Image Text:2.) This question builds somewhat on top of the previous
question. Instead of adding single bits at a time, let's
scale this up to two bits. This is visually represented
below:
+
Cout R1 RO
For this problem, you are given a carry-in bit `Cin`, as
well as the operands `A` and `B`, just as before. However,
`A` and `B` are now two bits apiece, with A0 holding
the bit at position 0 and `Al` holding the bit at position
1, and so on. This still produces `R` as a result, though
the result is now two bits large, with `R0` holding the
result value at position 0, and `R1` holding the result
value at position 1. `Cout holds the carry-out bit, as
before.
As before, fill in the table below. Note the ordering
of the inputs. The first few have already been completed
for you.
2a) 0
2b) 0
2c) 0
2d) 0
Cin Al B1 A0 B0 | Cout R1 R0
2e) 0
2f) 0
2h) 0
21) 0
2k) 0
2g) 0 0 1
0
0
A1 A0
В1 ВО
2r) 1
2s) 1
2j) 0 1 0
2t) 1
2u) 1
2v)
2w) 1
2x) 1
2y) 1
2z) 1
21) 0
2m)
2n) 0 1
O O O O O O OOHHddd□□□ O O O O O O OOHHHH
1
2aa) 1
0 0
2ab) 1
Cin
0 0
0 0
0 0
0 1
0 1
20) 0 1
2p)
2q) 1
0 1
1 0
1 0
1 0
1
1
0
0
1
нооооннН
0 1
1 0
1 0
2ac) 1
2ad) 1
2ae) 1
2af) 1 1
0
0
1
1
OOP
1 1
HHOOLHOOHH OOHHOOHH OOOOHH
1 1
1 0
1 1
0 0
0 | 0
1
| 0
0
| 0
1
0
1
1 0
0
1 1
1
0 0
1
1
1
1
0
TOTO
1
0 1 1 0
1
1 1
TOTO
0 1 1 1
1
OHOHOHOHOH
1 0 1 0
0
1 0 1 1
1
0
1
1 1 1 0
1 1 1
OOO
0 0
0 1
0 1
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