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2. To evaluate fr -dx, apply integration by parts twice. For the second application of integration by parts, what is the (In x)² x3 appropriate u and dv? u= -; dv= x dx In x X x² u= (In x)²; dv= 1 dx 1 U= dv= In x dx u= In x; dv= dx x3 A. B. C. D.

2. To evaluate fr -dx, apply integration by parts twice. For the second application of integration by parts, what is the (In x)² x3 appropriate u and dv? u= -; dv= x dx In x X x² u= (In x)²; dv= 1 dx 1 U= dv= In x dx u= In x; dv= dx x3 A. B. C. D.

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
ChapterA: Appendix
SectionA.2: Geometric Constructions
Problem 10P: A soda can has a volume of 25 cubic inches. Let x denote its radius and h its height, both in...
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2. To evaluate (in x)2 x³ -dx, apply integration by parts twice. For the second application of integration by parts, what is the appropriate u and dv? In x u=; dv= X 1 x² u= (In x)²; dv= dx 1 x³ 1 u= dv= ln x dx +3 1 u= ln x; dv= -dx x³ A. B. C. D. dx
Transcribed Image Text:2. To evaluate (in x)2 x³ -dx, apply integration by parts twice. For the second application of integration by parts, what is the appropriate u and dv? In x u=; dv= X 1 x² u= (In x)²; dv= dx 1 x³ 1 u= dv= ln x dx +3 1 u= ln x; dv= -dx x³ A. B. C. D. dx
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