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The base of a the y-axis are triangles with the height equal to 2. Algebraically, find the area of each triangle. 3 2 1 5432 423 4 O A(y)=√√9-y2 O A(y) = 1)= 1/2 √√/9-y² O A(y)=√√9-y² O A(y) = 2√√√9- y² 52345 -2 three-dimensional figure is bound by the semi-circle x = √9-y². Vertical cross sections that are perpendicular to

The base of a the y-axis are triangles with the height equal to 2. Algebraically, find the area of each triangle. 3 2 1 5432 423 4 O A(y)=√√9-y2 O A(y) = 1)= 1/2 √√/9-y² O A(y)=√√9-y² O A(y) = 2√√√9- y² 52345 -2 three-dimensional figure is bound by the semi-circle x = √9-y². Vertical cross sections that are perpendicular to

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.1: Equations
Problem 76E
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The base of a three-dimensional figure is bound by the semi-circle x = 1 the y-axis are triangles with the height equal to 2. Algebraically, find the area of each triangle. 5432 45 O A(Y) = O A(Y) = √9-y² O A(y) = √√9-y² O A(y) = 2√√√9-y² 80 F2 2 W S X # 3 E D C $ 4 R F % 5 SA V F5 T G MacBook Air F6 ^ 6 Y √9-y². Vertical cross sections that are perpendicular to 1 2 say 5 6 7 8 9 10 Next ▸ 4) B 87 & H F7 U N * 00* 8 4 J 1 P 1 9 F9 K M 1 O 0 F10 P
Transcribed Image Text:The base of a three-dimensional figure is bound by the semi-circle x = 1 the y-axis are triangles with the height equal to 2. Algebraically, find the area of each triangle. 5432 45 O A(Y) = O A(Y) = √9-y² O A(y) = √√9-y² O A(y) = 2√√√9-y² 80 F2 2 W S X # 3 E D C $ 4 R F % 5 SA V F5 T G MacBook Air F6 ^ 6 Y √9-y². Vertical cross sections that are perpendicular to 1 2 say 5 6 7 8 9 10 Next ▸ 4) B 87 & H F7 U N * 00* 8 4 J 1 P 1 9 F9 K M 1 O 0 F10 P
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