2. Two charged nested conducting spheres are pictured below. The inner sphere (radius r=5 cm) carries a charge of q=100 nC. The outer sphere has an inner radius r= 10 cm and outer radius of r=12.5 cm. The charge on the outer sphere is -300 nC. a) Use Gauss's law to determine the electric field in the following regions: < Scm Scm12.5cm

2. Two charged nested conducting spheres are pictured below. The inner sphere (radius r=5 cm) carries a charge of q=100 nC. The outer sphere has an inner radius r= 10 cm and outer radius of r=12.5 cm. The charge on the outer sphere is -300 nC. a) Use Gauss's law to determine the electric field in the following regions: < Scm Scm12.5cm

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter19: Electric Forces And Electric Fields

Section: Chapter Questions

Problem 12CQ

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Similar questions

A cylindrical shell of radius 7.00 cm and length 2.40 m has its charge uniformly distributed on its curved surface. The magnitude of the electric field at a point 19.0 cm radially outward from its axis (measured from the midpoint of the shell) is 36.0 kN/C. Find (a) the net charge on the shell and (b) the electric field at a point 4.00 cm from the axis, measured radially outward from the midpoint of the shell.
The electric field everywhere on the surface of a charged sphere of radius 0.230 m has a magnitude of 575 N/C and points radially outward from the center of the sphere. (a) What is the net charge on the sphere? (b) What can you conclude about the nature and distribution of charge inside the sphere?
A nonconducting, thin plane sheet of charge carries a uniform charge per unit area of 5.20 C/m2 as in Figure 15.30. (a) Find the electric field at a distance of 8.70 cm from the plate. (b) Explain whether your result changes as the distance from the sheet is varied.
A solid insulating sphere of radius R has a nonuniform charge density that varies with r according to the expression = Ar2, where A is a constant and r R is measured from the center of the sphere. (a) Show that the magnitude of the electric field outside (r R) the sphere is E = AR5/50r2. (b) Show that the magnitude of the electric field inside (r R) the sphere is E = Ar3/50. Note: The volume element dV for a spherical shell of radius r and thickness dr is equal to 4r2dr.
A uniformly charged spherical shell with positive surface charge density contains a circular hole in its surface. The radius r of the hole is small compared with the radius R of the sphere. What is the electric field at the center of the hole? Suggestion: This problem can be solved by using the principle of superposition.
Example 23.3 derives the exact expression for the electric field at a point on the axis of a uniformly charged disk. Consider a disk of radius R = 3.00 cm having a uniformly distributed charge of +5.20 C. (a) Using the result of Example 23.3, compute the electric field at a point on the axis and 3.00 mm from the center. (b) What If? Explain how the answer to part (a) compares with the field computed from the near-field approximation E = /20. (We derived this expression in Example 23.3.) (c) Using the result of Example 23.3, compute the electric field at a point on the axis and 30.0 cm from the center of the disk. (d) What If? Explain how the answer to part (c) compares with the electric field obtained by treating the disk as a +5.20-C charged particle at a distance of 30.0 cm.
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An uncharged, nonconducting, hollow sphere of radius 10.0 cm surrounds a 10.0-C charge located at the origin of a Cartesian coordinate system. A drill with a radius of 1.00 mm is aligned along the z axis, and a hole is drilled in the sphere. Calculate the electric flux through the hole.
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