Answer b and c. Also pls write out the answer so it will be easier to understand. Thank you! 2. Use the Fundamental Theorem of Calculus,(a)(b)(c)to evaluate the integrals:TT3sec x (secx + tan x) dx011/3(The Sec 08 ( Sec (1) + tan (1)) ott:05 ² ( Sic ² (x) + seclud tances aux= ³ Sec col de + 1²³3 (seclis ton Max[*(4x5/2+(sic²(x) dx = fantc, Ssc coastm(x) dx = sec(x+y)=> [tan (and ] == + [sec (x)}]}0= [tan () - tan/] + [See (5) - secilo))= [13-0) +(2+](4x5/2+3x3/2 - 2x¹/²) dxCπ/6 1 1[ (77-7/5- cos x) dxx3-3π/2• See (x) ( See (x) + ton (x) dx = √3 +1

2. Use the Fundamental Theorem of Calculus, (a) (b) (c) to evaluate the integrals: TT 3 sec x (secx + tan x) dx 0 11/3 50Th² secon ( See (in) + tance)) ok: 5²2 ( Sic² (17) + Selled kances aux = = [² ³ Sec col de + 1²³3 (seclis ton Max [sic²(x) dx = tante, (scoa ton²x) dx = => [tan (and ] == + [sec (x)}]} 0 = [tan () - tan/] + [See (5) - secilo)) = [13-0) +(2+] [*(4x5/2 + (4x5/2+3x3/2 - 2x¹/²) dx Cπ/6 [ (127 - 12/31 - cos x) dx x3 -3π/2 scelite) • See (x) ( =

2. Use the Fundamental Theorem of Calculus, (a) (b) (c) to evaluate the integrals: TT 3 sec x (secx + tan x) dx 0 11/3 50Th² secon ( See (in) + tance)) ok: 5²2 ( Sic² (17) + Selled kances aux = = [² ³ Sec col de + 1²³3 (seclis ton Max [sic²(x) dx = tante, (scoa ton²x) dx = => [tan (and ] == + [sec (x)}]} 0 = [tan () - tan/] + [See (5) - secilo)) = [13-0) +(2+] [*(4x5/2 + (4x5/2+3x3/2 - 2x¹/²) dx Cπ/6 [ (127 - 12/31 - cos x) dx x3 -3π/2 scelite) • See (x) ( =

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter6: Applications Of The Derivative

Section6.CR: Chapter 6 Review

Problem 20CR

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