2. When compared to f(x) = 3*, how does the graph of f (x) = -3x-5+ 1 differ? %3D A Shifted left 5 units and shifted down 1 unit. B Reflected over the y-axis, shifted 5 units to the right, and shifted down 1 unit. C Shifted right 5 units and shifted up 1 unit. D Reflected over the x-axis, shifted 5 units to the right, and shifted up 1 unit.

2. When compared to f(x) = 3*, how does the graph of f (x) = -3x-5+ 1 differ? %3D A Shifted left 5 units and shifted down 1 unit. B Reflected over the y-axis, shifted 5 units to the right, and shifted down 1 unit. C Shifted right 5 units and shifted up 1 unit. D Reflected over the x-axis, shifted 5 units to the right, and shifted up 1 unit.

Algebra and Trigonometry (MindTap Course List)

4th Edition

ISBN:9781305071742

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter4: Exponential And Logarithmic Functions

Section4.1: Exponential Functions

Problem 3E: a To obtain the graph of g(x)=2x1, we start with the graph of f(x)=2x and shift it ________...

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bThe average rate of change of the linear function f(x)=3x+5 between any two points is ________.
(a) To obtain the graph of g(x)=2x1 , we start with the graph of f(x)=2x and shift it _____________ (upward/ downward) 1 unit. (b) To obtain the graph of h(x)=2x1 , we start with the graph of f(x)=2xand shift it to the (left/right) 1unit.
a To obtain the graph of g(x)=2x1, we start with the graph of f(x)=2x and shift it ________ upward/downward 1 unit. b To obtain the graph of h(x)=2x1, we start with the graph of f(x)=2x and shift it to the ___________ left/right 1 unit.
Sketch the graph of fx=5e0.17x.
A company determines that its weekly profit from manufacturing and selling x units of a certain item is given by Px=-x3+3x2+2880x-500. Use a graphing utility to find the weekly production rate that will maximize the profit.
Now lets use a graphing calculator to get a graph of C=59(F32). By letting F=x and C=y, we obtain Figure 7.15. Pay special attention to the boundaries on x. These values were chosen so that the fraction (Maximumvalueofx)minus(Minimumvalueofx)95 Would be equal to 1. The viewing window of the graphing calculator used to produce Figure 7.15 is 95 pixels dots wide. Therefore, we use 95 as the denominator of the fraction. We chose the boundaries for y to make sure that the cursor would be visible on the screen when we looked for certain values. This was accomplished by setting the aforementioned fraction equal to 1 By moving the cursor to each of the F values, we can complete the table as follows. F 5 5 9 11 12 20 30 45 60 C 21 15 13 12 11 7 1 7 16 The C values are expressed to the nearest degree. Use your calculator and check the values in the table by using the equation C=59(F32).