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2.1Can you show me the steps to solve this problem?Directions: A particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. Find the velocity and the speed when t = 4.43) f(t) = 80t - 6t^2

Question

2.1

Can you show me the steps to solve this problem?

Directions: A particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. Find the velocity and the speed when t = 4.

43) f(t) = 80t - 6t^2

check_circleAnswer
Step 1

Given,

...
f(t) 80t 6t
df (t)
Since, velocity
dt
d(80t-6t2)
dt
80
6 x 2t
= 80 - 12t
So, velocity att = 4 is dF (t)
t 4
dt
= 80 12 x 4
32 m/s
=
Since, speed is the absolute value of velocity
So, speed at t 4 is 32 m/s
help_outline

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f(t) 80t 6t df (t) Since, velocity dt d(80t-6t2) dt 80 6 x 2t = 80 - 12t So, velocity att = 4 is dF (t) t 4 dt = 80 12 x 4 32 m/s = Since, speed is the absolute value of velocity So, speed at t 4 is 32 m/s

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Tagged in

Math

Calculus

Derivative

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