2.6 If H = 4a, - 3a, + 5a, at (1, 7/2, 0) %3D

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
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Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
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2.6 If H = 4a, – 3a, + 5a, at (1, 7/2,0) the component of H parallel to surface
p 1 is
(а) — За, + 5а,
(e) 5a, + 3a,
(a) 4a
(b) 5a,
(c) -3a
Transcribed Image Text:2.6 If H = 4a, – 3a, + 5a, at (1, 7/2,0) the component of H parallel to surface p 1 is (а) — За, + 5а, (e) 5a, + 3a, (a) 4a (b) 5a, (c) -3a
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