20 kN 50 kN 50 kN/m 25 kN/m B. 2 m 3 m

Q: 73.12 lb/in^2 to kg/m^2

A: Answer: 73.12 lb/in2 = 51400 kg/m2.

Q: 10 kN 2.5 kN•m 30° 1.5 m

A: The correct option is b.

Q: 3cm 3 Cum 4 Cun

A:

Q: 150 lb/ft A В -6 ft -8 ft

A: Let us draw the reaction at the supports  Weight of the rectangular load = 150 lb/ft(8ft)=1200 lb…

Q: 4 kN/m 2 m

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: Im 2 m 3 m

A:

Q: SG 3kN/m 1kN/m 2.4 m

A:

Q: 11.2 kN/m A B 2.8 m 3.1 m Fig. Q1 Note: not drawn to scale

A: To determine the reactions at A and B and to draw the hear force diagram.

Q: 2 kN/m 4 kN

A: Given data:

Q: E 4 ft G B D 12 kip 4 ft A 4 ft 4 ft 4 ft- -

A: A truss is a structural member, used to create rigid structures. The main function of the truss is…

Q: 50 KN/m 120 KN.m B- 9m 4m

A: For solution refer below images.

Q: A Mansard roof truss is loaded as shown. Determine the force in members GI, HI, and HJ.

A: Given data To determine the forces in the members GI,HI and HJ

Q: 40 kN E 2 m B F 3 m 50

A: to find reaction component at B and C

Q: 2T/m ΑΔ 3 m 6m 4T/m BA

A: Given problem consists of an overhanging beam supported by two hinge supports and acted upon by Two…

Q: 10 kN 0 r=2m 10 kN

A: Given data: Magnitude of the force = 10 kN Need to determine the magnitude of the couple about the…

Q: 500 lb 600 lb · ft A B -5 ft - -5 ft -5 ft

A: Forces and moments generated in any member depend upon the type of support and type of loading…

Q: 200 lb - 3 ft 3 ft - 50 Ib 30 -3 ft 100 lb

A: Data given-

Q: D 50 lb-ft B 4 in. 30 6 in. A.

A:

Q: 15 kN 25 kN 20 kN C В D 1 m 0.8 m 0.3 m 30 kN °0.4 m

A: Q7.35 Given: Load at A (P2)=15kNLoad at C (P1)=25kNLoad at D P3=30kNLoad at E (P4)=20kN

Q: Neglecting the mass of the beam, compute the reactions at A and B.

A:

Q: 2 KN/m 2 KN/m 3 m 3 m R R2

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: 30 EN 100 kN.m M-1200 KN m 2 m 3m 4 m 5m

A: Given: To draw SFD and BMD to calculate shear force and bending moment.

Q: 3 kN/m В 8 m 4 m D 10 m 5 kN H. = 5 kN A A M, = 66 kNm a Va= 24 kN

A:

Q: 12KN 4 kN /m 12m 24 KN 12m 36m 一- 10

A: Dear student, we are suppose to solve only one question. Please post other question as a separate…

Q: 100 lb 30° 200 lb 2 ft 300 ft-lb 2 ft 2 ft 2 ft-

A: First we resolved 100 lb force, and calculated horizontal force, vertical force and moment due to…

Q: 20 kN 40 kN 10 kN/m 1 m 2 m 2 m 2 m 1 m w

A: Before going through the calculation for shear force and bending moment calculation first, calculate…

Q: 8 kN 6 kN/m А С 1m 4 m 3 m m E.

A: Calculating the reaction at the support,

Q: 100 kN 64 kN 82 kN 82 kN 55 kN 2m A 3 m 3m 3 m 3 m 3m 3 m 91 kN 73 kN 46 kN

A:

Q: 1.5 m 4 kN A B 2 m 8 kN C D 2 m F E

A: Let  RFx and RFy are the horizontal and vertical reaction at F RE is vertical reaction at E By using…

Q: A 2 ft F, 4 ft M B. - 3 ft- 30 -x F,

A: Given that, F1=150 lb,F2=50 lbM=500 lb.ft Consider the given frame, Resolve the given force in two…

Q: 150 Ib/ft 100 lb

A: Consider the member AB and drawing FBD as shown below, Balancing vertical…

Q: 8 kN/m A

A: Calculate the reaction at the support, ∑Fx=0HA=0∑Fy=0VA+VB=8×6VA+VB=48   ......... (1)Due to…

Q: 6 kN/m B A-

A: we can see that variable distriubted load of 6 kN/m is acting for 9m.this variable distributed load…

Q: gure |2P Pro A |B -2 ft2 ft - –2 ft d 2 in.

A: For solution refer images.

Q: 100 KN 6m T

A: GIVEN DATA- A SIMPLY SUPPORTED BEAM GIVEN SUBJECTED TO POINT LOAD WE HAVE TO DRAW SFD AND BMD

Q: 12 KN 2.5 KN/M 介介企 A 12 m B 4m

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: 17 4-m 180 lbs 3-m 2-m 5-m 160 lbs

A:

Q: 3.5 ft 18 ft

A:

Q: |20 kN 15 kN/m A 2 m 4 m B.

A: The reactions on the supports of beam can be drawn as follows,

Q: 6 kN 2.5m

A: Write the equilibrium condition for the above problem.

Q: -5 at 3 m = 15 m- 12 kN 12 kKN |M IN 12 kN 12 kN 12 kN 12 kN L 20 kN– 4 m 40 kN- G 4 m 40 kN- 4 m 40…

A: The free-body diagram of the structure is shown as

Q: 10 KN/m 1a KN (m Ra 1.5 m 4m 3 m 1.5m

A: For solution refer below images.

Q: y 5 m 5 m A 5 m В 20 kN

A:

Q: (4) 18 kN 4 kN/m B 6 m -2 m

A: Question 4) is a propped cantilever beam

Q: 15 KN 18 kN 40 kN/m 3 m 6 m 4 m Fig.

A: To draw the SFD and BMD and determine the maximum bending moment

Q: 8 kN/m | 20 kN 4 kN/m 2.0 m 1.5 m

A: For solution refer below images.

Q: 100 kN I 120 kN/m 60 kN/m Ic D 315 kN-m 3 m 3 m 3 m 3 m

A: Draw the free-body diagram of the beam.

Q: 3.kN 30 kN/m B.

A: given; upper left beam; ⇒lets take reaction force at A=RA⇒lets take reaction force at B=RB⇒load…

Q: A Mansard roof truss is loaded as shown. Determine the force in members DF, DG, and EG.

A: Given: The loaded truss is shown below:

Conservation of Energy

In physics, the rule of the conservation of energy states that energy doesn’t disappear from the atmosphere; instead, it changes its form from one type to another. Energy is one of the most important physical quantities in nature, and it cannot be created or destroyed — only transformed.