= 20 mm m₁ = 476 Wdg/m n₂ = 300 Wdg f = 10.7 kHz = 10.7 x 10³ Hz Ho,theoretical = 4 x 10-7 N/A² 1.26 x 10-6 N/A² • Calculate the cross-sectional area of the induction coil: A = nr² = π (2 × 10-³) ² = • Write down the slope of the line: slope = [] = 3.81 • Using the relation emƒ = µ₁Аn₁n₂(2ƒ)I, calculate the experimental value for vacuum permeability: slope Ho,experimental An₂n₂ (2πf) • Calculate the error percentage: error % = Ho.theoretical Ho.experimentai Ho theoretical -x 100% =
= 20 mm m₁ = 476 Wdg/m n₂ = 300 Wdg f = 10.7 kHz = 10.7 x 10³ Hz Ho,theoretical = 4 x 10-7 N/A² 1.26 x 10-6 N/A² • Calculate the cross-sectional area of the induction coil: A = nr² = π (2 × 10-³) ² = • Write down the slope of the line: slope = [] = 3.81 • Using the relation emƒ = µ₁Аn₁n₂(2ƒ)I, calculate the experimental value for vacuum permeability: slope Ho,experimental An₂n₂ (2πf) • Calculate the error percentage: error % = Ho.theoretical Ho.experimentai Ho theoretical -x 100% =
Chapter13: Electromagnetic Induction
Section: Chapter Questions
Problem 30P: A long solenoid with n= 10 turns per centimeter has a cross-sectional area of 5.0 cm2and carries a...
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