21. Let f (x) = (x - 3)-². Show that there is no value of c in (1, 4) such that f (4) - f(1) = f'(c) (4-1). Why does this not contradict the Mean Value Theorem?
21. Let f (x) = (x - 3)-². Show that there is no value of c in (1, 4) such that f (4) - f(1) = f'(c) (4-1). Why does this not contradict the Mean Value Theorem?
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter14: Discrete Dynamical Systems
Section14.3: Determining Stability
Problem 1E
Related questions
Question
21
![21. Let f (x) = (x - 3)-². Show that
there is no value of c in (1,4) such
that f (4) f(1) = f'(c) (4-1).
Why does this not contradict the
Mean Value Theorem?
Answer
22. Let f(x) = 2 |2x - 1. Show that
there is no value of c such that
f (3)
f(0) = f'(c) (3-0). Why
does this not contradict the Mean
Value Theorem?
23-24 Show that the equation has
exactly one real solution.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F05718128-2692-4100-90eb-2bb7bf7cd66e%2Fea3f02b2-21bf-4a3f-be05-c957148135a2%2Fv72o2a7_processed.png&w=3840&q=75)
Transcribed Image Text:21. Let f (x) = (x - 3)-². Show that
there is no value of c in (1,4) such
that f (4) f(1) = f'(c) (4-1).
Why does this not contradict the
Mean Value Theorem?
Answer
22. Let f(x) = 2 |2x - 1. Show that
there is no value of c such that
f (3)
f(0) = f'(c) (3-0). Why
does this not contradict the Mean
Value Theorem?
23-24 Show that the equation has
exactly one real solution.
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