21.A solenoid 150 cm long with 1550 turns has a central magnetic field of 1.50 mT. Find the current through the coil. Which formula must be used for this problem? A. B = = M₂I 2πr B = N N H₂ I MI 2R F B = qvsine F B = II B. C. D.

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Author:Paul Peter Urone, Roger Hinrichs
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Chapter24: Electromagnetic Waves
Section: Chapter Questions
Problem 5PE: Verify the units obtained for magnetic field strength B in Example 24.1 (using the equation B=Ec )...
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21.A solenoid 150 cm long with 1550 turns has a
central magnetic field of 1.50 mT. Find the current
through the coil.
Which formula must be used for this problem?
O A.
B = =
MI
2лr
B = N
B =
B =
O
B.
C.
D.
NHI
2R
F
qvsino
F
Il
Transcribed Image Text:21.A solenoid 150 cm long with 1550 turns has a central magnetic field of 1.50 mT. Find the current through the coil. Which formula must be used for this problem? O A. B = = MI 2лr B = N B = B = O B. C. D. NHI 2R F qvsino F Il
19.A long, straight wire allows 3.50 A through it. What
is the magnitude of the magnetic field 25.0 cm from
the wire? Express the answer in microTesla (µT). Write
magnitude only, unit is already given.
A.
F
B =
qvsino
MI
B =
=
2лr
мол
B = NH
2R
F
B =
Il
B.
C.
D.
Transcribed Image Text:19.A long, straight wire allows 3.50 A through it. What is the magnitude of the magnetic field 25.0 cm from the wire? Express the answer in microTesla (µT). Write magnitude only, unit is already given. A. F B = qvsino MI B = = 2лr мол B = NH 2R F B = Il B. C. D.
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