23 22-1 dz (1- 22(2 +2i]3

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A:

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Q: 2. 1.5 sin(3t-

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Q: 2 2 In sin 2x - 2 In (1 + cos 2x) = In ( )- %3D

A: Given that: The identity is 2 ln sin 2x - 2 ln ( 1 + cos 2x) = 2 ln tan x .

Q: 19 · sin 0 = 5 -4 7t 7n 11n B) {", Ila, 6. 6.

A: Given that, -4 - 25 · sin θ = -19    5   - 25 · sin θ=-19    5 +4-25 · sinθ=-19+205sin θ=15·-52sin…

Q: 3. 4 cos 2 s2-4sin = 5 %3D -

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Q: tan(2 – j5) j(2-j5) +7- jv2 In(-5)| (3220° – sin 20 + jln5)*|

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Q: 19. f(8) = 8 - sin²(20) 9 8sin(20)cos(20) a. f'(0) = 9 32sin (20)cos(20) b. f'(8) = 9 32cos(20) c.…

A: fθ=89sin22θ take derivative f'θ=ddθ89sin22θ

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A:

Q: 1 sinx # 1-cos2x ẩu! (6 2

A: Given query is to find the value of the limit.

Q: 6) 1-cosx %3D 1+cosx (cotx - cscx)2

A:

Q: 10x 19) y Sin'(5x') (ans.: JI-25 x' 20) y= Cot ) (ans.: 1+ x' 6x' 21) y=tan'V4x'- 2 (ans.: (4x'-1…

A: As per guidelines we can only solve first question or first three subparts of the question, I am…

Q: 20. е -3.1х cos 2.1x, e -3.1х sin 2.1x

A:

Q: 12. Show that the equation z + iz + 1 = 0 has neither a real root nor a purely imaginary root.

A: Note: According to bartleby we have to answer only first question please upload the question…

Q: 1/6 2 +3 sin 0 cos 20 1/6 2 +3 sin 0 (T %3D COS Gos 20

A:

Q: tan (58°) 1.40 m (1.4 m)(tan58°) = x (1.4 m)(tan58°) %3D х%3D (1.4)(1.6) II

A: Given that   Based on the provided information

Q: 13 A Iz =, arg (z) =tan-(8)- 13 B arg (z) =n-tan-(8)

A: the given complex number is 3-2j2j+1 rationalize…

Q: 9=3 Sin 2X 2.

A: answer is in next step

Q: Graphing a Trigonometric Function In Exercises39–48, use a graphing utility to graph the…

A: Hello. Since your question has multiple parts, we will solve first question for you. If you want…

Q: 2π tane 13-12cose de

A: We will find thw integral.

Q: sin(2³ + 42) f(2) = %3D 2² – 2z + 5

A: In this question, we find the radius of convergence for the given function. For the radius of…

Q: 125 cos – j sin 11 7T 11 1. Simplify . Express answer in rectangular form. 47 + jsin 11 J5 cos 11

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: 1 sin(2.x): sin(2x) -125 %3D (D²-1)' true false

A:

Q: 43. If |2| > 2, then f - dr r = fcos(5) + k B sin-'(5) + k: cosh-" (5) + k: Itanh-"(4)+k B 2

A: by using hyperbolic Trigonometry substitution

Q: (sin 31)8(1-a/2)dt

A:

Q: dN + N = Ntet+2 dt

A: we have to solve first order of differential equation given below

Q: 1 3n sin 3x + 3. |-23 8.

A:

Q: 11) Verify the identity: sec 2x-1 sec' x-1= sec 2x +1

A: We start with the right side

Q: 5. 4 f sin + 2zdz

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Q: tan(2 – j5) j(2-j5) +7- jv2 In(-5) (320° – sin 20 + jln5)*

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Q: 2 16n |xV8 - x³ dx: 9/3 3 11) Show that

A: Properties of Beta Function:  β(m, n)=∫01xm-11-xn-1dxβ(m, n)=Γ(m)Γ(n)Γ(m+n) ;       m>0,  n>0…

Q: 7/4 *(1 – sin 2t)3/2 cos 2t dt

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Q: sin + 4 4 can be expanded to: sin sin 4 4 cos cos 4 o sin - cos 4 sin 4 sin 4 o cos -sin 4 + cos 4…

A: Solve the following

Q: 3) [I - cos х х

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Q: 7/4 26. * sec*e tan 0 de sec*0 tan*o de

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Q: 5. [(6+3z)cos(1+4:)dz

A: To evaluate the given integral.

Q: neN JS E (4i +1) = 2n2 + 3n +1 n(n +1) . neN JI

A:

Q: 13л +i sin 16 5л +i sin 8. 13л 5л Let Z1 = 10| cos and Z, = 2| cos 16 8

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Q: 2. 4-cose 1 de =

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Q: tan(0) Insec(0) de (A (Insec(0))²+C (Insin(0))²+C 2 - (Intan(e)) ²+C D -Incos (0) + C 2

A: We have to evaluate the integral ∫tanθlnsecθdθ For this, we shall use the method of substitution.

Q: Can i get help step by step with this problem?

A: Given integral is

Q: (cos 20+ jsin 20) (cos 60+ jsin 60)1" (cos 30+ jsin 30)°(cjs 1000)

A: the given expression is cos 2θ+jsin 2θ5cos 6θ+jsin 6θ10cos 3θ+jsin 3θ9cjs 10θ Using De Moivre's…

Q: 4.) Ž(1-sin1)* k=0 codh bs nohsrmotru betroupon or to lla bnit: I- 0pibcipojn BwGr p odmgon: 5.) n=2

A:

Q: 3元 4) sin 5元 5) sec 4

A: Given,          sin3π2

Q: 5) 2/3cos Osin 0- cos 0 = 2cos 0

A: Please see the answer below.