24Vdc is applied as the Vcc of a Common-Emitter amplifier. Which of the following sets of dc voltage (with respect to ground) measurements indicate a properly biased Common Emitter Amplifier? Justify your answer. Set A: Vc = 20 V, V8 = 1.46V, VẸ = 790mV Set B: Vc = 22 V, V8 = 1.8V, VẸ= 1.45V %3D Set C: Vc = 22.7V, V8 = 0.9V, Vɛ = 600mV
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- The dc bias circuit for a common emitter amplifier is shown in the figure. In the circuit, Vcc=15v,RB1=20k Ω,RB2=100k Ω,Rc=5.1k Ω,and RE1=1k Ω, Assume that when the transistor is on, the voltage drop from base to emitter VBE=0.7v. Also assume that β= ∞, which implies that the base current can be considered zero (IB=0) in your calculations. Solve for the base voltage VB. Solve for the emitter voltage VE. Solve for the emitter current IB. Solve for the collector current ICIf the circuit of problem 2 is configured as a common-emitter amplifier, calculate the resulting voltage and current gain. Assume a load resistor of 1k ohm. Circuit of problem 2: determine the operating point of a universal trasnsistor DC bias cirucit when Vcc=15V, R1=10k ohm, R2=2.2k ohm, Rc=680 ohm, Re=100 ohm. Assume beta (b)=200 and Vbe=0.72V.Design a Single-Stage Common Emitter Class A Amplifier Specifications:Voltage Divider Bias Circuit Supply: Any value from 10Vdc to 24VdcLoad: 1kΩVoltage Gain: Any value from 80 to 400Lower Cutoff Frequency: 100 HzSinusoidal source (zero internal resistance): 50mVp-pTransistor: Si, β = 75 • Base-Collector capacitance = 8pF • Base-Emitter Capacitance = 25pF a) compute for the biasing resistances.b) determine the dc transistor terminal voltages and transistor currents.
- [16:36, 16.06.2021] Mücahit Sezgin: The common-emitter amplifier given in the figurein the circuit, Vcc=9V, R1=27kΩ, R2=15kΩ,RE=1.2kΩ and RC=2.2kΩ. Transistor β=100has value.[16:36, 16.06.2021] Mücahit Sezgin: a-) If it has values of Rsig=10kΩ and RL=2kΩCalculate the IE of the amplifier. b-) For small signal analysis of transistorFind the value of Rin by deriving the π-model c-) Calculate vo/vsig and io/ii.In the common-emitter amplifier circuit shown in the figure, Vcc=9V, R1=27kΩ, R2=15kΩ, RE=1.2kΩ and RC=2.2kΩ. The transistor has β=100.a-) If Rsig=10kΩ and RL=2kΩ, calculate the IE value of the amplifier.b-) For small signal analysis of the transistor, find the value of Rin by deriving the π-modelc-) Calculate vo/vsig and io/ii.Question 1: Draw and explain the transistor amplifier, which is usually referred as emitter follower.Also, (i) derive its voltage and current gains by equivalent circuit; (ii) compare its voltage and current gains with other transistor amplifiers. Question 2:(a) Predict the name of the curve drawn between ID and VGS of the JFET and represent the cut off voltage in it. (b) E-MOSFET has ID(on) = 600mA (minimum) at VGS = 9V and VGS(th) = 1 V. Find the drain current for VGS = 6 V. Question 3: (a) State the name of the power amplifier, which has a efficiency as 10% in practical case and also derive and prove its theoretical efficiency is 25%. (b) Explain the role of Q point in power amplifiers based on its location in AC load line.…
- What is the voltage gain of the common-emitter amplifier as shown? Assume βF = 135, VCC = VEE = 10 V, R1 = 20 kΩ, R2 = 62 kΩ,RC = 13 kΩ, and RE = 3.9 kΩ.for a common emitter amplifier shown (beta=100) (R1=15k, R2 = 8.2k) Compute for Zin, Zout, Bre, Rth, Vc, Vb, Ib, Voltage Gain, and Current Gain4) By drawing the small signal model of the circuit given below, we can determine the total voltage and current gain values of the circuit, without the bypass capacitor on and without the bypass capacitor. Calculate separately for the two cases as it will be in the circuit (connected to the emitter end of the transistor). (β = 100, rS = 600 Ω, R1 = 27 KΩ, R2 = 4.7 KΩ, RC = 3.3 KΩ, RE = 680 Ω, RL= 15 KΩ, VCC = 10 V)
- Since Vcc = 12 V, Vin = 690 mV, RB = 780 kΩ, RC1 = 27.9 Ω, RC2 = 25.4 Ω, RE = 470 Ω, RL = 47 Ω and β1 = β2 = 100 in the circuit in the figure Find the current (IL) flowing through RL? NOTE-1: VBE1 = VBE2 = 0.7 V will be taken. NOTE-2: Output impedances of transistors (r0) will be neglected.a) Differentiate between Common Emitter (CE), Common Collector (CC) and Common Base (CB) amplifiers. b) Do the DC Analysis of the circuit below and find out the DC collector voltage?c) Do the AC Analysis of the circuit below and find out the AC collector voltage?R1=30kΩΩ=610ΩThe transistor is specified to have Bf in the range of 7 to 35. The load resistance is Rc = 9 ohms. The dc supply voltage is Vcc = 180V and the input voltage to the base circuit is VB = 8V. If VCE (Sat) = 1,1 V and VBE (sat) = 1,6, determine: The value of RB that results in an ODF of 4 A. 0,7514 ohm B 0,5634 ohm C. 0,5081ohm D. 1 ohm The Power loss in the Transistor A. 35,07 W B. 44,30 W c. 40,04 W D. 23,65 W