The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 25.5 m/s is h = 2 + 25.5t - 4.9t2 after t seconds.(a) Find the velocity (in m/s) after t seconds.v(t) =Find the velocity (in m/s) after 2 seconds and after 4 seconds.v(2) =X m/sv(4) =X m/s(b) What is the value (in m/s) of v(t) when the projectile reaches its maximum height?v(t) =m/sWhen (in s) does the projectile reach its maximum height? (Round your answer to two decimal places.)४ s(c) What is the maximum height (in m)? (Round your answer to two decimal places.)X m(d) When (in s) does it hit the ground? (Round your answer to two decimal places.)(e) With what velocity (in m/s) does it hit the ground? (Round your answer to two decimal places.)X m/s

Answered: Image /qna-images/answer/9c2a6dcd-f1db-45b9-ad63-459a3f2d014c.jpg

25.5 m/s is h = 2 + 25.5t - 4.9t after t seconds. (a) Find the velocity (in m/s) after t seconds. v(t) = Find the velocity (in m/s) after 2 seconds and after 4 seconds. v(2) = x m/s v(4) = X m/s (b) What is the value (in m/s) of v(t) when the projectile reaches maximum height? v(t) = m/s When (in s) does the projectile reach its maximum height? (Round your answer to two decimal places.) (c) What is the maximum height (in m)? (Round your answer to two decimal places.) X m (d) When (in s) does it hit the ground? (Round your answer to two decimal places.) (e) With what velocity (in m/s) does it hit the ground? (Round your answer to two decimal places.)

25.5 m/s is h = 2 + 25.5t - 4.9t after t seconds. (a) Find the velocity (in m/s) after t seconds. v(t) = Find the velocity (in m/s) after 2 seconds and after 4 seconds. v(2) = x m/s v(4) = X m/s (b) What is the value (in m/s) of v(t) when the projectile reaches maximum height? v(t) = m/s When (in s) does the projectile reach its maximum height? (Round your answer to two decimal places.) (c) What is the maximum height (in m)? (Round your answer to two decimal places.) X m (d) When (in s) does it hit the ground? (Round your answer to two decimal places.) (e) With what velocity (in m/s) does it hit the ground? (Round your answer to two decimal places.)

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 7OQ: A projectile is launched on the Earth with a certain initial velocity and moves without air...

See similar textbooks

Similar questions

A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 146 feet per second from an initial height of 89 feet off the ground, then the height of the projectile, h, in feet, t seconds after it's shot is given by the equation: h=−16t2+146t+89h=-16t2+146t+89 Find the two points in time when the object is 126 feet above the ground (to one decimal places). Answer: The object is 126 feet off the ground at the following times: (Enter your two answers separated by a comma. Round to ONE decimal places.)
A ball thrown horizontally with an initial velocity of = 23.0 m/s travels a horizontal distance of d = 58.0 mm before hitting the ground. From what height h was the ball thrown? using the equation provided solve for h which is the same as Yinitial Yfinal = 0 Yinitial = ? Initial velocity of y = 9.8 m/s gravity = 9.8 m/s Change in time = 35 s
The height (in meters) of a projectile shot vertically upward from a point 4 m above ground level with an initial velocity of 25.5 m/s is h = 4 + 25.5t − 4.9t2 after t seconds. When does it hit the ground and at what velocity does it hit the ground
A cannonball is fired from the ground with anupward initial velocity of 30 m/s. If the cannonball reaches a height of 5 meters, what is its y-velocity? Use g = 10 m/s^2 a. sqrt of 10 m/s b. 10 m/s c. 12 m/s d. 15 m/s
The height (in meters) of a projectile shot vertically upward from a point 3 m above ground level with an initial velocity of 22.5 m/s is h = 3 + 22.5t − 4.9t2 after t seconds. When does it hit the ground? With what velocity (in m/s) does it hit the ground?
The height (in meters) of a projectile shot vertically upward from a point 4 m above ground level with an initial velocity of 25.5 m/s is h = 4 + 25.5t − 4.9t2 after t seconds. When does the projectile meet its maximum height and what is its maximum height?
The height of an object thrown upward from the roof of a building 408 ft. tall, with a initial velocity of 96 ft/ sec, is given by the equation h= -16t2+96t+408, where h represents the height of the object after t seconds. How long will it take the object to hit the ground?. Answer in exact form and decimal form rounded to the nearest hundredth.
A balloon is ascending with a velocity of v = 3.09 when a stone is released.If the height at the time of release is h = 441, how long does it take thestone to reach the ground? Present two solutions with different referencepoints. Thanks
a man can throw a ball a maximum horizontal distance of 58.7m the acceleration of gravity is 9.8 m/s^2 How far can he throw the same ball vertically upward with the same initial speed? answer in units of m
A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 146 feet per second from an initial height of 89 feet off the ground, then the height of the projectile, hh, in feet, tt seconds after it's shot is given by the equation: h=−16t2+146t+89h=-16t2+146t+89 Find the two points in time when the object is 126 feet above the ground (to one decimal places). Answer: The object is 126 feet off the ground at the following times: (Enter your two answers separated by a comma. Round to ONE decimal places.)
A car moves on a straight road such that its position from a reference point is given by the following function:{ x(t) = 3 + 5t + 2t2 + 0.4t3, y(t) = 0, z(t) = 0 }where t is in seconds and x in meters. Find the average velocity, in meters per second, in the x-direction between t1 = 0.25 s and t2 = 1.85 s. Find the average acceleration, in meters per second squared, in the x-direction between t1 = 0.25 s and t2 = 1.85 s.
The height of a helicopter above the ground is given by y(t)=4.5t^(2), in meters. After 2.0 seconds the helicopter releases a mailbag, how long does it take for the mailbag to hit the ground?