26. A telescope is made with a hyperbolic mirror, shown graphed on the coordinate plane. To assemble the telescope correctly, the manufacturer needs to know the distance to the focus on the same side as the reflective side of the mirror. What is this distance? What equation represents the location of the mirror? SEE EXAMPLE 4 16 24 (12-50) (0-5) -16 -24

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EXAMPLE 4 Use a Hyperbola to Model a Real-World Situation
Some telescopes use a hyperbolic mirror. Light is directed inward at the
hyperbolic mirror. It is reflected through a hole in the parabolic mirror
is shown on a coordinate plane. What equation can be used to represent the
toward a focus, where it can be captured by a detector. A hyperbolic mirror
mirror? How far must the detector be placed from the mirror?
Hyperbolic Secondary Mirror
Parabolic Primary Mirror
Focal
Point
F
mirror
(6, 3)
d
focus/
(5,0) focus
One of the vertices is at (5, 0), so a = 5. A given point on the hyperbola is (6, 3).
y²
= 1
6²
= 1
62 32
52 6²
36
The foci are on the x-axis,
so this is a horizontal
hyperbola. Use the form
9
35-2=1
x²y²
a²b²
= 1.
36b²-225=
256²
11b² = 225
b² = 20.5
The equation that models this hyperbolic mirror is - 20.5 = 1.
The detector would have to be placed at the focus of the other branch of the
hyperbola, at the point (-c, 0). Since c²= a² + b², the coordinates for the
detector are (-√45.5, 0) or about (-6.7, 0) which is about 11.7 units away
from the mirror.
light
I
Transcribed Image Text:EXAMPLE 4 Use a Hyperbola to Model a Real-World Situation Some telescopes use a hyperbolic mirror. Light is directed inward at the hyperbolic mirror. It is reflected through a hole in the parabolic mirror is shown on a coordinate plane. What equation can be used to represent the toward a focus, where it can be captured by a detector. A hyperbolic mirror mirror? How far must the detector be placed from the mirror? Hyperbolic Secondary Mirror Parabolic Primary Mirror Focal Point F mirror (6, 3) d focus/ (5,0) focus One of the vertices is at (5, 0), so a = 5. A given point on the hyperbola is (6, 3). y² = 1 6² = 1 62 32 52 6² 36 The foci are on the x-axis, so this is a horizontal hyperbola. Use the form 9 35-2=1 x²y² a²b² = 1. 36b²-225= 256² 11b² = 225 b² = 20.5 The equation that models this hyperbolic mirror is - 20.5 = 1. The detector would have to be placed at the focus of the other branch of the hyperbola, at the point (-c, 0). Since c²= a² + b², the coordinates for the detector are (-√45.5, 0) or about (-6.7, 0) which is about 11.7 units away from the mirror. light I
26. A telescope is made with a hyperbolic mirror,
shown graphed on the coordinate plane.
To assemble the telescope correctly, the
manufacturer needs to know the distance to
the focus on the same side as the reflective
side of the mirror. What is this distance?
What equation represents the location of the
mirror? SEE EXAMPLE 4
8 16 24
(12-50)
(0-5)
-16
-24
Transcribed Image Text:26. A telescope is made with a hyperbolic mirror, shown graphed on the coordinate plane. To assemble the telescope correctly, the manufacturer needs to know the distance to the focus on the same side as the reflective side of the mirror. What is this distance? What equation represents the location of the mirror? SEE EXAMPLE 4 8 16 24 (12-50) (0-5) -16 -24
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