27.4. A particle with mass 1.81 × 103 kg and a charge of v 1.22× 108 Chas, at a given instant, a velocity = (3.00 × 10¹ m/s)ĵ. What are the magnitude and direction of the particle's acceleration pro- duced by a uniform magnetic field B = (1.63 T)i + (0.980 T)Ĵ?

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter30: Magnetic Fields And Forces
Section: Chapter Questions
Problem 90PQ: A mass spectrometer (Fig. 30.40, page 956) operates with a uniform magnetic field of 20.0 mT and an...
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27.4. A particle with mass 1.81 × 103 kg and a charge of
1.22× 10-8 Chas, at a given instant, a velocity 7 = (3.00 × 10¹ m/s)ĵ.
What are the magnitude and direction of the particle's acceleration pro-
duced by a uniform magnetic field B = (1.63 T)i + (0.980 T)Ĵ?
Transcribed Image Text:27.4. A particle with mass 1.81 × 103 kg and a charge of 1.22× 10-8 Chas, at a given instant, a velocity 7 = (3.00 × 10¹ m/s)ĵ. What are the magnitude and direction of the particle's acceleration pro- duced by a uniform magnetic field B = (1.63 T)i + (0.980 T)Ĵ?
27.3. In a 1.25 T magnetic field directed vertically upward, a particle
having a charge of magnitude 8.50 μC and initially moving northward
at 4.75 km/s is deflected toward the east. (a) What is the sign of the
charge of this particle? Make a sketch to illustrate how you found your
answer. (b) Find the magnetic force on the particle.
Transcribed Image Text:27.3. In a 1.25 T magnetic field directed vertically upward, a particle having a charge of magnitude 8.50 μC and initially moving northward at 4.75 km/s is deflected toward the east. (a) What is the sign of the charge of this particle? Make a sketch to illustrate how you found your answer. (b) Find the magnetic force on the particle.
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