Consider an electric potential as a function of the distance r,12AV(r) = (1- ²/ ((₁-²4) (₁ + ¹24² ) - 1).2What happens to the electric field at r = 6A?OA. E>0OB. E<0OC. E=0OD. Ē→ ∞

Answered: Image /qna-images/answer/f15e9972-a88b-4a73-846a-1b3a7d20f8af.jpg

Answered: 2A V(r) = - ²2/((1-²4) (₁+¹24²)-1).…

2A V(r) = - ²2/((1-²4) (₁+¹24²)-1). Consider an electric potential as a function of the distance r, What happens to the electric field at r = OA. É > 0 O B. E<0 OC. E=0 O D. E- 6A?

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter20: Electric Potential And Capacitance

Section: Chapter Questions

Problem 24P

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

Consider an electric potential as a function of the distance r,
1
2A
V(r) = (1
- ²/ ((₁-²4) (₁ + ¹24² ) - 1).
2
What happens to the electric field at r = 6A?
OA. E>0
OB. E<0
OC. E=0
OD. Ē→ ∞

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