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2х1 + X2 — Хз — 5 {3x1 + 3x2 2xз — 8 X1 + x2 + x3 = 6

2х1 + X2 — Хз — 5 {3x1 + 3x2 2xз — 8 X1 + x2 + x3 = 6

Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter6: Fractions
Section6.1: Simplifying Fractions
Problem 36WE
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Solve the system, using Gaussian elimination method

 

2х1 + X2 — хз — 5 2x1 + {3х1 + 3x2 — 2хз 3D 8 X1 + x2 + x3 = 6
Transcribed Image Text:2х1 + X2 — хз — 5 2x1 + {3х1 + 3x2 — 2хз 3D 8 X1 + x2 + x3 = 6
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