2HI (g) H2(g) + I2(g) At equilibrium the partial pressures are as follows : PHI = 0.708 atm,, PH2 and PI2 are 0.0960 atm. What is the value of Kp ? 6.80 × 10-2 1.30 x 10-2 1.84 x 10-2 4.70 × 10-2
2HI (g) H2(g) + I2(g) At equilibrium the partial pressures are as follows : PHI = 0.708 atm,, PH2 and PI2 are 0.0960 atm. What is the value of Kp ? 6.80 × 10-2 1.30 x 10-2 1.84 x 10-2 4.70 × 10-2
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 123QRT
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Step 1
• The given reaction is,
2HI(g) ⇌ H2(g) + I2(g)
• The values provided in the question are:-
i) Equilibrium partial pressure of HI, PHI = 0.708 atm
ii) Equilibrium partial pressure of H2, PH2 = 0.0960 atm
iii) Equilibrium partial pressure of I2, PI2 = 0.0960 atm
• We need to calculate the equilibrium constant, Kp in terms of pressure for the reaction.
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