2s – 3 F(s) s2 + 2s + 10

Q: 2(s-3) L-1 s²–6s+13) (ix) 3s+2 (x) L- (s2-8s+25)

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Q: -2 -1 2 1 -3 T x = y²-3 y = x-1 4 2 3 5 6

A: The given graph is  We have to find the area of the given curve using the vertical rectangle.

Q: 5s-2 d. s²(s+2)(s-1)

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Q: y = -2x+4 y 3z-11a-8 The Set Up: Standard Form: -() ±VO-4OO 2() 土、 X= 土

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Q: x²e 6. S (х2+1)2

A: Given : ∫x3ex2x2+12dx

Q: 6 (c) 5n n%3D1 3n2 + 12n - 6 5n4-3n2 + 8 (d)

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Q: .2 P(x)%=3x-4x³ +2x+3x-6 What value does P(x) approach as x becomes very large? 8.

A: In this question we have to find what value does P(x) approach as x becomes very large.

Q: A. y = - (x – 2)2 B. y = -(x - 2)2 C. y = (x + 2)? D. y = -(x + 2)² 7. A. y = -4(x + 2)² + 1 B. y =…

A: General form of parabola is: y=ax-h2+k........(i) , where h,kis coordinate of vertex and x,y is any…

Q: g(n)=2n+1 h(n)=-2n 2 +1 Findg(3) ̧h(3)

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Q: Ўitsўіхву. ч. +8 Ця +7ўz FЧу; таўст бу, 2 * Чуа +2y=0 20

A: As per the question we are given a system of second order linear homogeneous differential equations…

Q: 5s+3 6s 8 F(s) - (5s2+4s+1) s2+7 9.

A: The laplace transform formulas for e^(at)cos(bt) and e^(at)sin(bt) will be used in solving this…

Q: 2 (d²y + x3 = 0 -x | 2. 3.

A: We have to find the following conditions according to the given information

Q: ) F:( -3 7 1 2 0 0 2 1 -3 -2 0 2 E: 3 -1 4 1 3 1

A: Consider the matrix as, E=-2023-14131 Use elementary transformations to convert to Echelon Form.…

Q: 4 9 5- .2 13) =D1 7 2+-+ X x²

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Q: z + 2ī +3 – i = 0 1-i2 z – 2z = 1+i7

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Q: 2(k, e) = (-2)* f(k – () + 2/9 + /3l. %3D |

A: The given equation is,                       z(k,l)+2z(k-1,l-1)=l ....................(i) let k-l=m

Q: 3. XSつち =6 -E 2. 3 2. こ -ソ= 4cs2x

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Q: 3. y' = 5y + e-2*y-2 y(0) = 2 У (0) - 4. хуу' + 4x2 + у? 3D 0 о у(2) 3 —7

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Q: fs=メー4 f(3)3= %3D

A: Substitute the value of x in given equation

Q: 3s² +5s+5 F(s) = (s3+8s²+19s+12)(s³)

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Q: 9. x= (2- 1); 1E [0, 5] y = (t- 3)²

A: In algebra, an equation can be defined as a mathematical statement consisting of an equal symbol…

Q: f(x) %3D — х3 + х2 — 8х + 4 1. 3.

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Q: 2z - 8| 0 | ² + |z + i|² < 2. ≥ 1, show that 1+z+z²+

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Q: 3. A = {x € Z +|x 3}|

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Q: 3メ - 6 Vx -2 2) S + 2 ると、メ (3x²-4) -16 4り(E-ネ。 2x

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Q: X +2y-44 2 = 0 5X+3リ -2oス=0 -X+ネス =。 => {A !0)

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Q: 2 4 + 27 (-2)" 16 + 243 Σ %3D - 3n+k n=1 9. 81 what must be the value of k?

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Q: k 2. ΣΡ 0(-1) * Lk%30 k+1

A: Alternating series. Test

Q: e-7x - 2e3 et f (x) = e- *+16e10* + 2e-4z

A: (a) Consider the provided limit, limx→-∞e-7x-2e3x-exe-x+16e10x+2e-4x Evaluate the provided limit.…

Q: f(n) = 2f(n-1) + 3f(n-2) %3D

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Q: Use Cramer’s Rule to solve the given system:

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Q: 22 -3z + 2 5. f(z) = |3D (z 1)2(z - 3)3

A: As you asked only for question number 5 so I do only question number  5.

Q: (D^3 - D^2 +4D -4)y=8-e^x + 4cos(2x)

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Q: -6 3 4. f (x) -5 -1 1

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Q: 3-2t %3D 5t-15 t+2 10. 3t-9 19-t 15-t b. 15 (-3) 3t+8 5-t a. 15(t-3) C. 15 (t-3) 8(t-3)

A: Hello! thank you for the question but as per our honor code, we'll able to solve only the first…

Q: x³dx 3. S х2+3х+2

A: We will solve the problem

Q: 3(% 1)2 dz; z-21

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Q: Use matrices to solve the system.

A: x+3y-z=-3  3x-y+2z=12x-y+z=-1

Q: method. (a) 1 (s-a)(s-b) s² +1

A: Solution 1(a): Given function is 1(s-a)(s-b) Let the partial fraction of above be…

Q: y = (b) -8 -2 ere to search - 6 y 2 -4 -6 -8 1 -4 2 4 1 y 2 61 -4 6 8 O 6 2 8 DELL X X 3. A

A: We have to find the equation of graph

Q: n3 - 2 1. Find Lt n+0 2n° + 3n - 4

A: Simplify the fraction and solve the limit.

Q: |sgn(-2.4)|+sgn(-0.2) = 2 TO FO

A: Note: Since, you haven't mentioned which question you would like to get answered. Here, we are…

Q: y = -x-4 X-y= -6 (-5,1)

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Q: 2х - 5у +z%3D10 Z. —х+3у = -4 x-2y+2z = 9

A: Given: 2x-5y +z = 10 -x +3y = -4 x -2y+2z = 9 To solve: The system of equations.

Q: g1 (x) -2 11 -1 8 1 -1 g1 (x) -2 -11 -1 -8 0. -5 1. -2 1 5, 2. 2.

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Q: 5 6) f(r)= I -3 f(-3) = f(-4)= f(0) =

A: To find the function values (of the function defined in a piecewise manner)

Q: 3. К(а)3D|a — 2, find k(-9) Solution: k(-9) =. k(-9) =9 – 2 k(-9) = 4. p(а) %— -4а — 2, find p(2a)…

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Q: V2 /2 /2/2] V2/2 (2 1 1 A = /2/2 -1 v2/2 -1 -V2]

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Q: X -2 -1 0 1 2 y=-4x3 + 2x+1 현 1" 2nd 30 X -2 -1 0 1 2 3 y = -3x4 + x-1 D 1st 2nd 30 4th

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Q: (-2) = –3, g'(-2) = 6, (f g)'(-2) = 15. Find g(-2) %3D

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