3) Find the arclength of the following curve on the given interval. x = 31, y= 41; 1

Q: Find the arc length of the graph of the function over the indicated interval.

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Q: Find the exact arc length of the curve over the stated interval. y = 7x/2 – 5, from x = 0 to x = 1 -…

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Q: Find the arc length of the graph of the function over the indicated interval. 3/2 + 1 y = y 6 4 -1 1…

A: y=23x2+132 Differentiating with respect to x, we get dydx=23·32x2+132-1·dx2+1dx=x2+112·2x=2xx2+112

Q: Find the arc length of the graph of the function over the indicated interval. x = (1)/(3)(y2 +…

A: Given x=13y2+232 ,0 ≤ y ≤ 8.

Q: Find the arc length of the graph of the function over the indicated interval. y -m (anon).

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Q: Find the exact arc length of the curve over the stated interval. y=x²³ from x=1 to x=8

A: Please see the below picture for detailed solution.

Q: Find the arc length of the graph of the function over the indicated interval x = ² 글(v2+ 2)3/2,…

A: Given x =13y2+23/2 ...(1)   0≤y ≤5Differentiating (1) with respect to y, we get f'(y) =dxdy =…

Q: In the given question , find the arc length of the graph of the function over the indicated…

A: Given function is y=32x23,  1, 8

Q: Find the arc length of the following curves on the given interval. 1 for 1 8y2" X = + 4 y . 2

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Q: Find the arc length of the curve y = (x² – 8 In(x)) from x 2 to x = 5. |

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Q: Find the arclength of y = 2x3/2 on the interval x is greater than or equal to 1 and less than or…

A: Equation of given curve is y=2x32 Differentiate with respect to x. dydx=232x32-1=3x

Q: Find the arc length of the graph of the function over the given interval:

A:

Q: Find the arc length of the curve below on the given interval. 1 y = + 6. on [1,2] 4 16x

A: As per Bartleby guidelines for more than one question asked only one is to be answered please upload…

Q: Find the arc length of the following curve on the given interval. x=24t+8, y = 7t+3, 0≤t≤2 The…

A: Given equation of function is  x=24t+8,y=7t+3, 0≤t≤2 The arc length of the given function is…

Q: Find the arc length of the curve on the indicated interval of the parameter. x = 8t + 5, y = 5t – 3,…

A: Arc length of the curve between intervals a and b is given by:

Q: Find the arc length of the following curve on the given interval. x= 12, y = 18r, 0sts vE

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Q: Find arc-length of the following curve 0 <t < 2 x = sin (t) Y = cos'(t)

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Q: Compute the arclength of the following curves. (y-1)³ =x², for 0 <x< 5 а.

A: We have to compute the arc length for the function y-13=x2, for 0≤x≤5.

Q: Find the arc length of the curve on the indicated interval of the parameter. X = 6t + 5, y = 5t – 4,…

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Q: Find the arc length of the curve below on the given interval. とマ 1 X=- , for 2sys4 8y 4 The length…

A: We know that length of curve x=f(y) from y=a to y=b is L=∫ab1+dxdy2dy

Q: a) Show that the length of the arc of the curve y=f(x) where S(x) = Insecx 0SxS is 4 In(1+ v2)

A: We need to show that the length of the arc of the curve y=f(x) where f(x)=ln(sec(x)), 0≤x≤π4. The…

Q: Find the arc length of the following curve on the given interval. y = 3x +7 on [-3, 1]

A: We know that the arc length of a curve y=f(x) on an interval [a, b] is given by L = ∫ab1+dydx2 dx

Q: Find  the  arc length of the following curve on the given interval. y=1/2x^3/2 on [0,60]

A:

Q: Find the arc length of the curve below on the given interval. 1 y%3= (x +6) 2 on (0.3] 3/2 on [0,3]

A: We find dy/dx using the power rule and chain rule

Q: Find the arc length of the graph of the function over the indicated interval.

A:

Q: Find the arclength of the curve below over the interval -1<t<1

A: Here we have to find the arc length of the given curve.

Q: Find the arc length of the curve y between <x <4, with y given as y = In (sin (2x))

A:

Q: find the arc length of the curve on the given interval:

A: We find dx/dt and dy/dt

Q: Find the exact arc length of the curve over the stated interval. y = 4x2/3, from x = 1 to x = 64 %3D…

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Q: Find the arc length of the graph of the function over the indicated interval.

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Q: x = 4 sint, y= In(1+t), (-2<t <1).

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Q: Find the arc length of the graph of the function over the indicated interval. X = 3 Vyv - 3), 1<y s…

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Q: Given x = y² + y + 1 from 0 ≤ y ≤ 2

A: To find the arclength of the following curve

Q: 3. Find the exact arc length of the curve y = 2Vx' on the interval [0,11]. ( -. TV +70 +60 +50 +40…

A: To find  The exact arc length of the given curve.

Q: 3. What is the arc length of y=e* from x= 1 to x=5? Draw the curve

A: Given: The curve function y=ex from x=1 to x=5 Find the arc length of the given curve also draw the…

Q: Find the exact arc length of the curve over the interval from y = 1 to y = 4 1 1 + -2 x =

A:

Q: Find the exact arc length of the curve over the stated interval.  x = 1/8 y^4 + 1/4 y^-2, from y =…

A:

Q: b) y = ln (cos x) 0 <x<- 3

A: Given: y=ln(cosx) in the interval 0≤x≤π3

Q: Find the arc length of the curve on the given interval x (0) = 0³, y (0) = 0² ; 0 ≤ 0 ≤ 2

A:

Q: Find the arc length of y = 7r +1 over the interval [0, 2]

A: y = 7r + 1 arc length=∫02 1+(dy/dr)2dr dy/dr = 7' arc length=∫02 1+(7)2dr arc length=∫02 50dr arc…

Q: Find the exact arc length of the curve over the stated interval. y = 5x3/2 – 2, from x = 0 to x = 1…

A: This is geometry problem

Q: calculate the arc length over the given interval y = x3/2, [1, 2]

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Q: Find the arc length of the curve defined by y = In x over the interval 1sxse.

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Q: Calculate the arclength of the following curve on the given interval. y%=2x3/2+1O on the interval…

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Q: Find the exact arc length of the curve over the stated interval. 1 1 +y2, from y = 1 to y = 4 x = 4°

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Q: Calculate the arc :length of the curve y = In(2x + 1) over the interval

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Q: x= - y2 from y=1 to y=9 1/2

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Q: 1. Find the arc length of the curve y = on the interval [0, 60]. n i len

A: Answer is 168 Explanation is given below..

Q: 1 Find the arc length of the curve y = + 4 from (0, 4) to (1, ).

A:

Q: 1. Compute the arc length of the curve y = t, over the interval (0 < x < 2). 6 x y

A: Since you have asked multiple question, we will solve the first question for you. If you want any…