3 If f(x) x-7x 9, show that there are values c for which f(c) equals (a) e, (b) 3, and (c) 5,000,000 (a) The function f is a polynomial, which is everywhere-continuous. What is the best way to begin the problem? O A. Find values of x, and x for which f(x)0 or f(x2) 0 O B. Find values of x1 and x2 for which f(x1)s0s f(x2) or f(x1)202 f(x2) Find values of x1 and x2 for which f(x,)sesf(x2) or f(x1)2e2 f(x2). C. O D. Find values of x1 and x2 for which f(x)se and f(x2)se or f(x1)2e and f(x2)2e. Use the trial and error method. Begin by finding f(-4) f(-4) (Simplify your answer.) Now, find f( 3 - (Simplify your answer.) f(-3) Does a solution exist between -4 and 3 for f(x) =e? Inconclusive, because f(-4)<0 but f-3)>0. O O Inconclusive, because e does not lie between f-4) and f(-3) Yes, because f(-4)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
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Chapter4: Polynomial And Rational Functions
Section4.1: Polynomial Functions Of Degree Greater Than
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If f(x) x-7x
9, show that there are values c for which f(c) equals (a) e, (b) 3, and (c) 5,000,000
(a) The function f is a polynomial, which is everywhere-continuous. What is the best way to begin the problem?
O A. Find values of x, and x for which f(x)0 or f(x2) 0
O B.
Find values of x1 and x2 for which f(x1)s0s f(x2) or f(x1)202 f(x2)
Find values of x1 and x2 for which f(x,)sesf(x2) or f(x1)2e2 f(x2).
C.
O D. Find values of x1 and x2 for which f(x)se and f(x2)se or f(x1)2e and f(x2)2e.
Use the trial and error method. Begin by finding f(-4)
f(-4)
(Simplify your answer.)
Now, find f( 3
-
(Simplify your answer.)
f(-3)
Does a solution exist between -4 and 3 for f(x) =e?
Inconclusive, because f(-4)<0 but f-3)>0.
O
O Inconclusive, because e does not lie between f-4) and f(-3)
Yes, because f(-4)<e <f(-3).
Transcribed Image Text:3 If f(x) x-7x 9, show that there are values c for which f(c) equals (a) e, (b) 3, and (c) 5,000,000 (a) The function f is a polynomial, which is everywhere-continuous. What is the best way to begin the problem? O A. Find values of x, and x for which f(x)0 or f(x2) 0 O B. Find values of x1 and x2 for which f(x1)s0s f(x2) or f(x1)202 f(x2) Find values of x1 and x2 for which f(x,)sesf(x2) or f(x1)2e2 f(x2). C. O D. Find values of x1 and x2 for which f(x)se and f(x2)se or f(x1)2e and f(x2)2e. Use the trial and error method. Begin by finding f(-4) f(-4) (Simplify your answer.) Now, find f( 3 - (Simplify your answer.) f(-3) Does a solution exist between -4 and 3 for f(x) =e? Inconclusive, because f(-4)<0 but f-3)>0. O O Inconclusive, because e does not lie between f-4) and f(-3) Yes, because f(-4)<e <f(-3).
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