T max = 8.106 ksiomax = 11.516 ksiomin = -4.516 ksi|T max = 4.717 ksiomax = 10.217 ksiomin = 0.783 ksi|T max = 3.606 ksiomax = 9.606 ksiomin = -2.394 ksiT max = 3.606 ksiomax = -2.394 ksiomin = -9.606 ksi 44 ksi3 ksi70S ksiGiven the state of stress above (ignore 70° plane): calculate the maximum shearstress, maximum principal stress and minimum principal stress in this order.Choose only one answer.

To find maximum shear and principal stress

Answered: 3 ksi S ksi iven the state of stress…

3 ksi S ksi iven the state of stress above (ignore 70° plane): calculate the maximum she ress, maximum principal stress and minimum principal stress in this order.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Solid Mechanics

Engineering mechanics is a branch of science that deals with forces causing bulk motion in bodies and the effect that these forces cause on the bodies. Engineering mechanics does not deal with the internal changes that occur on account of these external forces. The internal effects in a body or a material under the action of external forces are studied in a new branch of science called solid mechanics, the strength of materials, or the mechanical behavior of engineering materials.

Question

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T max = 8.106 ksi
omax = 11.516 ksi
omin = -4.516 ksi
|T max = 4.717 ksi
omax = 10.217 ksi
omin = 0.783 ksi
|T max = 3.606 ksi
omax = 9.606 ksi
omin = -2.394 ksi
T max = 3.606 ksi
omax = -2.394 ksi
omin = -9.606 ksi

44 ksi
3 ksi
70
S ksi
Given the state of stress above (ignore 70° plane): calculate the maximum shear
stress, maximum principal stress and minimum principal stress in this order.
Choose only one answer.

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