3 m B -3 m- -3 m- C 2.25 m k = 200 N/m- -3 m D E 4 m F 3 m 3 m 3m 3 m A -0-90° p=0.1 -2m-1m- F(x)= -Inx Inx+-Inx F(x)= -Inx -Inx boundary from x=1 to x = 2 + In(cos~¹((√1- (sin(x))²))) boundary from x=1 fox = 2 In(cos-¹((√1- (sin(x))²))) N cm Activate Wir Go to Settings t cm What is the change in length of the spring?
3 m B -3 m- -3 m- C 2.25 m k = 200 N/m- -3 m D E 4 m F 3 m 3 m 3m 3 m A -0-90° p=0.1 -2m-1m- F(x)= -Inx Inx+-Inx F(x)= -Inx -Inx boundary from x=1 to x = 2 + In(cos~¹((√1- (sin(x))²))) boundary from x=1 fox = 2 In(cos-¹((√1- (sin(x))²))) N cm Activate Wir Go to Settings t cm What is the change in length of the spring?
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter2: Axially Loaded Members
Section: Chapter Questions
Problem 2.8.12P: A bungee jumper having a mass of 55 kg leaps from a bridge, braking her fall with a long elastic...
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