3 moles of an ideal gas undergoes an isothermal expansion at constant temperature T = 290 K, its pressure changes from P1 = 143.74 kPa to P2 = 87.67 kPa. Calculate the work done by the gas.

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter17: Energy In Thermal Processes: The First Law Of Thermodynamics
Section: Chapter Questions
Problem 31P: An ideal gas initially at 300 K undergoes an isobaric expansion at 2.50 kPa. If the volume increases...
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3 moles of an ideal gas undergoes an isothermal expansion at constant temperature T = 290 K, its pressure changes from P1 = 143.74 kPa to P2 = 87.67 kPa. Calculate the work done by the gas.

3 moles of an ideal gas undergoes an isothermal expansion at constant temperature T = 290 K, its pressure changes from P₁
= 143.74 kPa to P₂ = 87.67 kPa. Calculate the work done by the gas.
-3570.26 J
O 3570.26J
O 1190.09J
O 2580.91 J
Transcribed Image Text:3 moles of an ideal gas undergoes an isothermal expansion at constant temperature T = 290 K, its pressure changes from P₁ = 143.74 kPa to P₂ = 87.67 kPa. Calculate the work done by the gas. -3570.26 J O 3570.26J O 1190.09J O 2580.91 J
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