3) Run the C code below, and explain why it doesnt display the exact decimal number you expect. You may write it by Java ( System.out.printf("%.20f", val);) #include I/ floating point representation error int main() { float i, t=0.0, a=1.0, b=10.0, c; for (i=0; i<100; i++) t=t+0.1; printf("\n adding 0.1, 100 times t=%10.20f",t); t=0.13; printf("\n just displaying 0.1 =%10.20f",t); printf("\n result of 1/10 =%10.20f",1/10); c=a/b; printf("\n c=%10.20f",c); system("pause"); }

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter7: User-defined Simple Data Types, Namespaces, And The String Type
Section: Chapter Questions
Problem 1TF
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Please explain why. Thank in advance!

3) Run the C code below, and explain why it doesnt display the exact decimal number you
expect. You may write it by Java ( System.out.printf("%.20f", val);)
#include <stdio.h>
I/ floating point representation error
int main()
{ float i, t=0.0, a=1.0, b=10.0, c;
for (i=0; i<100; i++)
t=t+0.1;
printf("\n adding 0.1, 100 times t=%10.20f",t);
t=0.13;
printf("\n just displaying 0.1 =%10.20f",t);
printf("\n result of 1/10 =%10.20f",1/10);
c=a/b;
printf("\n c=%10.20f",c);
system("pause"); }
Transcribed Image Text:3) Run the C code below, and explain why it doesnt display the exact decimal number you expect. You may write it by Java ( System.out.printf("%.20f", val);) #include <stdio.h> I/ floating point representation error int main() { float i, t=0.0, a=1.0, b=10.0, c; for (i=0; i<100; i++) t=t+0.1; printf("\n adding 0.1, 100 times t=%10.20f",t); t=0.13; printf("\n just displaying 0.1 =%10.20f",t); printf("\n result of 1/10 =%10.20f",1/10); c=a/b; printf("\n c=%10.20f",c); system("pause"); }
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