3 sec 4x tan 4xdx 9/1 T/12

Q: 6x sec(x) tan(x)dx

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Q: 11. sec(x) /sec(x)+ tan(x)dx

A: To find the value of the integral ∫secxsecx+tanxdxUsing Integration by partsAccording to it…

Q: 1. S[3 + tan(4x²)J²xdx

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Q: dx 9x2-2

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Q: [5 sec x tan x dx %3D

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Q: S sec²(4x)(3 – tan(4x))³dx

A: Given integral is ∫ sec24x3-tan4x3dx.

Q: e* secʻ(e* +1dx tan(e* +1) 8. 2x² – 7x -5 9. 2x+1

A: 8) Consider ∫ex sec2(ex+1)tan(ex+1)dx                       (1) Let tan(ex+1) = t On differentiating…

Q: 5. y = 5 tan x³ + sec (3x)

A: Topic = Derivative

Q: 7. tan' x secx dx

A:

Q: S(4 sec x + 3 tan x)²dx

A: We will solve the problem

Q: Find 7/3 tan'x sec*x dx 27.

A: Since you have posted multiple questions i can do first question as per our company guidelines…

Q: 7/2 [sec¹ x tan³ x dx 4. 0

A: As per bartleby guidelines we only give first question answers. Please repost for other parts.

Q: (B) Evaluate tan (5x +1) sec³(5x +1) dx

A: We have to evaluate the integral.

Q: 4 sec 2x tan 2x dx (1+ sec 2x)²

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Q: Describe why the statement is incorrect

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Q: 7 (e) S( + 2sec(2x)tan(2x))dx 1+x

A: (e) Given integral is ∫71+x2+2sec2xtan2xdx Use property ∫afxdx=a∫fxdx…

Q: S tan (2x)sec (2x)dx = %3D

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Q: 2 S tan"(3x 1)sec (3x 1)dx - |

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Q: sec (2x) dx (tan 2x-4)"

A: We have  ∫sec2(2x)tan2x-43dxLet  tan2x=u    diff. w.r.t x we get2sec2(2x)= dudx sec2(2x)dx=12du now…

Q: (tan'x de 3 1. [cse* xdx 4 2. csc"xdx 3. |tan 3x sec 3xdx

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Q: 6. sech(4x) tan (4x) dx

A: We need to evaluate integral.

Q: (B) Evaluate | tan (5x+1) sec³(5x+1) dx

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Q: 2/3 " tan'x sec'x dx X.

A: Solving the problem by doing the definite integral.

Q: (Vian tan³ x + 1) sec" x dx

A:

Q: TT/3 4. sec x tan x dx sec3 x T/6

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Q: 3. y= (sec ³x + tan ²x)

A: Topic:- application of derivatives

Q: evaluate the integral.

A: Let,

Q: S sec²(3 – 2x)dx

A: ∫sec23-2x dx Put, 3-2x=t⇒0-21=dtdx⇒-2 dx=dt⇒dx=-dt2

Q: tan (2x)sec (2x)dx 3

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Q: Evaluate 2. S sec*x tan*xdx

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Q: S 4 sec(x) tan(x) dx

A: We will use standard formula here

Q: 1. Evaluate 4 (sec²x tan²x ). dx

A: Use product rule of differentiation du·vdx=vdudx+udvdx. Use chain rule of differentiation…

Q: 8) S(tan(7x) sec(7x)) dx

A: Solving the problem by doing the integration.   NOTE :: As per our Expert guidelines we are supposed…

Q: Evaluate the integrals

A: Integration is summation of discrete data. The integral is calculated for the functions to find…

Q: 1. Evaluate (sec²x tan²x ). dx

A: To find dsec2x tan2xdx Given function is y=sec2x tan2xwe know that, sec2x =1+tan2xthen…

Q: 14) y = tan (x) b. a. 10- 10- -10- c. 10- 10- 10-

A:

Q: ∫sec^2(x)dx

A: The given integral is ∫sec2x dx

Q: Evaluate ſ tan2 2x sec 2x dx 4

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Q: Evaluate the integrals

A: To evaluate: ∫0π4sec2x1+7tanx23dx Let substitute t=1+7tanx dtdx=ddx1+7tanxdtdx=7sec2xdt7=sec2xdx…

Q: Verify the identity

A: We have to prove

Q: 4. sec 4x tan 4x dx

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Q: tan 2x sec' n²2x sec 2x dx

A: Evaluate: ∫tan22xsec52xdx

Q: 5. Use 2- step substitution tan 4x sec² (4x) dx

A: To solve the integration

Q: ∫(〖sec〗^2 xdx)/(1+tanx)

A: Given: ∫sec2xdx1+tanx

Q: 14. sec xdx 2 3/2 (1 – 4 tan x)³/²

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Q: 4 sec2 x tan ydx + sec² y tan xdy = 0.

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Q: 25. | (3— 2 tan? 5х) sec2 5x dx

A: Solve the following integral

Q: Sec tan (5x) dx

A: